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3 years ago

Use the figure below to determine the relationship between _DBE and BED

Mathematics

1 answer:

victus00 [196]3 years ago

7 0

Using the relationships between the sides of a triangle and their opposite angle the relationship between
Third option
The opposite angle to the side DE=5 is the The opposite angle to the side BD= 12 is the angle< BED
The side DE= 5

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Ivan has a piece of material that is 4 feet long. He cuts it into 7 equal pieces. Which equation shows how to find the length, i

Drupady [299]

You have not provided the options, but this solution is an equation that will work:

Answer:

4 / 7 = x

Step-by-step explanation:

Since the total material is 4 feet long, we can divide 4 feet by 7, the number of equal pieces cut, to see how long each piece is.

This gives us an answer of 4/7 or about 0.571

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2 years ago

PLSSS HELP IMMEDIATELY!!!!!!! only answer if u know. i’ll be giving brainiest if u don’t leave a link.

Nana76 [90]

Answer:

Sides: Isosceles

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3 years ago

Read 2 more answers

87/80 into a mixed number in lowest terms no links or ill report.

svp [43]

Answer:

1 7/80

Step-by-step explanation:

1 and 7 over 80

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3 years ago

Sean buys a packet of perfumed candles that contains 12 lavender, 8 vanilla, and 20 rose-perfumed candles. He randomly takes

11111nata11111 [884]

Answer:

05.

Step-by-step explanation:

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3 years ago

Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.

Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ , we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

$= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}$

$= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\$

$= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C$

substitute u = 1-2x⁵ into the result

$= \dfrac{1}{40(1-2x^5)^4} +C$

Hence $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ $= \dfrac{1}{40(1-2x^5)^4} +C$

5 0

3 years ago

Use the figure below to determine the relationship between _DBE and BED​

Use the figure below to determine the relationship between _DBE and BED