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Maurinko [17]
3 years ago
13

Evaluate the expression: 12-3x3-2 O 12 O9 O 25 0 1

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

12-3×3-2

12-6-2

12-11

1

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A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.
maxonik [38]

Answer:

135.5ft

Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

X² = 3600 + Y²

if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

8 0
3 years ago
Evaluate each permutation 7p3
enot [183]
If you have a graphing calculator, you could use it to solve this question.

If you have a TI-84, go to <em>MATH</em> then <em>PROB</em> then <em>3: nPr</em>

From there, all you have to do is type in 7 and 3 in their correct spots to get 210 as your answer.
3 0
4 years ago
11/4= AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
jekas [21]

Answer:

2.75

Step-by-step explanation:

\frac{11}{4}  = 2\frac{3}{4 }  = 2.75

Hope this works....

5 0
3 years ago
Read 2 more answers
Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5
user100 [1]
Let d be distance travelled when they are level , and t = time that nora took to get level with mason for Nora 6 = d/t d = 6t for Mason 5 = d / (t + 35) d = 5 ( t + 350 so 6t = 5(t + 35) solve for t
7 0
3 years ago
Determine the intercepts of the line. y=−2x−21
yuradex [85]
Hi there!

Let's first determine the x-intercept. When dealing with an x-intercept we must realise the y-coordinates equal 0.

y = - 2x - 21 \\ y = 0 \\ \\ - 2x - 21 = 0
Add 21 to both sides.

- 2x = 21
Divide both sides by -2.

x = \frac{21}{2} = 10 \frac{1}{2}
Therefore, the x-intercept is the point (10 1/2; 0).

--------------------------------------
Now let's continue with the y-intercept, which is easier. When dealing with an y-intercept we must realise the x-coordinates equal 0.

y = - 2x - 21 \\ x = 0 \\ \\ y = - 2 \times 0 - 21 = - 21
Therefore, the y-intercept is the point (0; -21).
4 0
3 years ago
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