What is 1/5 the speed of a cat

a recipe for 1 loaf of bread calls for 2 cups of flour, 12 tablespoons of water, and 1 teaspoon of salt. The recipe can be scale

natulia [17]

Answer:

Step-by-step explanation:

A recipe for 1 loaf of bread calls for 2 cups of flour, 12 tablespoons of water and 1 teaspoon of salt.

Therefore, if we add 2 loaves of bread then double of ingredients will be required for the recipe.

In the same way if 4 loaves of bread have been added, 4 times ingredients will be required.

If 3 cups of flour are added then 3 times of other ingredients will be required.

So the table will be,

Number of loaves Cups of flour Tablespoons of water Teaspoons of salt

1 2 12 1

2 4 24 2

4 8 48 4

3 6 36 3

4 0

2 years ago

Maths!

Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

X $X-\bar X$ $(X-\bar X)^{2}$

5 5 - 8 = -3 9

8 8 - 8 = 0 0

10 10 - 8 = 2 4

9 9 - 8 = 1 1

6 6 - 8 = -2 4

Total 72 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{72}{9}$ = 8

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

X $X-\bar X$ $(X-\bar X)^{2}$

7 7 - 10 = -3 9

10 10 - 10 = 0 0

12 12 - 10 = 2 4

11 11 - 10 = 1 1

8 8 - 10 = -2 4

Total 90 36

Firstly, the mean of the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{90}{9}$ = 10

(1)Now, the variance of the given data is;

Variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$

= $\frac{36}{9-1}$ = 4.5

So, the new standard deviation, (S.D.) = $\sqrt{\text{Variance}}$

= $\sqrt{4.5}$ = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly is that it remains unchanged as we see in the case of variance or standard deviation.

4 0

3 years ago

The Bureau of Labor Statistics1 in the US tells us that, in 2010, the unemployment rate for high school graduates with no colleg

mars1129 [50]

Answer:

$p_1 -p_2 = 0.097-0.052 = 0.045$

So then the difference between the two proportions is 0.045 and if we convert this into % we got

$0.045*100= 4.5%$

Step-by-step explanation:

For this case we can define the following notation:

$p_1$ represent the unemployment rate for high school graduates with no college degree

$p_2$ represent the unemployment rate for college graduates with a bachelor's degree

And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:

$p_1 -p_2$

From the info given we have $p_1 = \frac{9.7}{100}=0.097$

$p_2 = \frac{5.2}{100}=0.052$

And the difference:

$p_1 -p_2 = 0.097-0.052 = 0.045$

So then the difference between the two proportions is 0.045 and if we convert this into % we got

$0.045*100= 4.5%$

5 0

3 years ago

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts

Alexxandr [17]

Answer:

The value of the test statistic is $t = 2.67$

Step-by-step explanation:

The null hypothesis is:

$H_{0} = 7.8$

The alternate hypotesis is:

$H_{1} \neq 7.8$

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

In this problem, we have that:

$X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16$

Then

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}$

$t = 2.67$

The value of the test statistic is $t = 2.67$

5 0

3 years ago

Bruh I need help ion know this stuff

ArbitrLikvidat [17]

I believe the answer is b and e

3 0

2 years ago

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