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hammer [34]
2 years ago
9

Instead of dividing $15.00 by 2 1/2, double both numbers and then find the quotent.

Mathematics
1 answer:
MAVERICK [17]2 years ago
7 0
6 because its 6 dont ask
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Construct a triangle POT having side OT= 7cm​
Sladkaya [172]

Answer:

Answer is No.

Reason:

One side of the triangle has to be less than the sum of the other two sides and greater than the magnitude of their difference.

i.e.,

Rule 1: (side1 + side2) > side3

Rule 2: Side3 < |side1 - side2|

Lets check the fact by adding / subtracting two sides and comparing with the third one..

Case1: 7+ 8 = 15 = length of third side. Rule1 fails

Case2:

8+15 > 7 Rule1 sucess

15–8 = 7 = length of third side. Rule 2 fails.

Case3:

7+15>8 Rule1 success

15–7=8 = length of third side. Rule 2 fails.

So, considering the rules and checking the facts..

It is impossible to create a triangle with above 3 sides.

8 0
3 years ago
Read 2 more answers
What is the y-intercept of the graph of the line whose equation is y=3/4x+1
Tanzania [10]

Answer:

The correct answer is "1".

Step-by-step explanation:

You need only set x to zero, and solve for y:

y = \frac{3}{4} x + 1\\y = \frac{3}{4}0 + 1\\y = 1

4 0
3 years ago
In the triangle below, what is tan θ?
jok3333 [9.3K]
Tan theta = 12/5

Hope it helps.
4 0
3 years ago
Read 2 more answers
Can someone please help me
nadya68 [22]

Answer:

<u>Right</u><u> </u><u>option</u><u> </u><u>is</u><u> </u><u>B</u><u>.</u><u> </u>

Step-by-step explanation:

\sf  \longrightarrow \frac{ \sec x \sin( - x)  +  \tan( - x) }{1 +  \sec( - x) }  \\  \\  \sf \longrightarrow  \frac{ \sec x( -  \sin x) -  \tan x}{1 +  \sec x}  \\  \\  \sf  \longrightarrow   \frac{  - \frac{1}{ \cos x } \times  \sin x -  \tan x }{1 +  \sec x}  \\  \\  \sf  \longrightarrow \frac{ -  \tan x -  \tan x}{1 +  \sec x}   \\  \\  \sf  \longrightarrow  \frac{ - 2 \tan x}{1 +  \sec x}  \\  \\  \sf \longrightarrow   \frac{  \frac{ - 2 \sin x}{ \cos x} }{1 +  \frac{1}{ \cos x} }  \\  \\  \sf  \longrightarrow  \frac{  \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} }  \\  \\     \boxed{  \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1}  }}

4 0
1 year ago
Which point is a solution to y ≤ 3x- 4?<br> O A. (0,4)<br> O B. (-2, 0)<br> OC. (0, 0)<br> OD. (3,1)
Nina [5.8K]

Answer:

<em>(D). (3, 1) </em>

Step-by-step explanation:

y ≤ 3x - 4

<u><em>(A). (0, 4)</em></u>

4 ≤ 3(0) - 4

4 ≤ - 4 <u><em>(False statement)</em></u>

<u><em>(B). (-2, 0)</em></u>

0 ≤ 3(- 2) - 4

0 ≤ - 10 <u><em>(False statement) </em></u>

<u><em>(C). (0, 0)</em></u>

0 ≤ 3(0) - 4

0 ≤ - 4 <u><em>(False statement)</em></u>

<u><em>(D). (3, 1)</em></u>

1 ≤ 3(3) - 4

1 ≤ 5 <u><em>(True statement) </em></u>

4 0
3 years ago
Read 2 more answers
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