Because there is a +e and a -e in the two equations we can simply add them together to solve for d...
2d+e+d-e=8+4 combine like terms
3d=12 divide by 3
d=4, now use this d in either original equation to solve for e...<span>d–e=4 so
4-e=4 subtract 4
-e=0
e=0
So the solution, where the lines intersect graphically, is the point (4, 0)</span>
-2 times -2 will give you 4 or (-2 x -2=4)
-8 times -2 will give you 16 or (-8 x -2=16)
16 times -2 will give you -32 or (16 x -2=-32)
Answer:
X = 3
Step-by-step explanation:
STEP 1: Isolate a square root on the left hand side
Original equation
√4x-3+√2x+3 = 6
Isolate
√4x-3 = -√2x+3+6
STEP 2: Eliminate the radical on the left hand side
Raise both sides to the second power
(√4x-3)2 = (-√2x+3+6)2
After squaring
4x-3 = 2x+3+36-12√2x+3
STEP 3: Get remaining radical by itself
Current equation
4x-3 = 2x+3+36-12√2x+3
Isolate radical on the left hand side
12√2x+3 = -4x+3+2x+3+36
Tidy up
12√2x+3 = -2x+42
STEP 4: Eliminate the radical on the left hand side
Raise both sides to the second power
(12√2x+3)2 = (-2x+42)2
After squaring
288x+432 = 4x2-168x+1764
STEP 5: Solve the quadratic equation
Rearranged equation
4x2 - 456x + 1332 = 0
This equation has two rational roots:
{x1, x2}={111, 3}
STEP 6: Check that the first solution is correct
Original equation, root isolated, after tidy up
√4x-3 = -√2x+3+6
Plug in 111 for x
√4•(111)-3 = -√2•(111)+3+6
Simplify
√441 = -9
Solution does not check
21 ≠ -9
STEP 7: Check that the second solution is correct
Original equation, root isolated, after tidy up
√4x-3 = -√2x+3+6
Plug in 3 for x
√4•(3)-3 = -√2•(3)+3+6
Simplify
√9 = 3
Solution checks !!
Solution is:
x = 3