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1 year ago

Can someone please help me

Mathematics

1 answer:

nadya68 [22]1 year ago

4 0

Answer:

Right option is B.

Step-by-step explanation:

$\sf \longrightarrow \frac{ \sec x \sin( - x) + \tan( - x) }{1 + \sec( - x) } \\ \\ \sf \longrightarrow \frac{ \sec x( - \sin x) - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \frac{1}{ \cos x } \times \sin x - \tan x }{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \tan x - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - 2 \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{1 + \frac{1}{ \cos x} } \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} } \\ \\ \boxed{ \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1} }}$

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A girl scout has (5x+18)

zhannawk [14.2K]

Step-by-step explanation:

(5x+18) - (3x+12)

5x+18=3x+12

5x-3x=2x

18-12=6

2x+6

3 0

3 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago

Choose all the fractions that are in simplest form. 4/26 8/21 6/19 9/10 10/22

dimulka [17.4K]

4/26 can be simplified by 2. So, this is not the answer.
8/21 cannot be simplified. So, it is one of the answers.
6/19 cannot be simplified. So, it is one of the answers.
9/10 cannot be simplified. So, it is one of the answers.
10/22 can be simplified by 2. So, this is not the answer.

So, the fractions in simplest forms are 8/21, 6/19, and 9/10.

3 0

3 years ago

53 - 9y = 1 -7.2 + 2y = -5

telo118 [61]

Answer:

1.1, -5

Step-by-step explanation:

53 - 9y = 1

from equation i

53-9y = 1

-9y= 1-53 = -52

y = -52/-9= 52/9 = 5⁷/₉

-7.2 + 2y = -5

add 7.2 to both sides

2y= -5+7.2 = 2.2

y= 2.2/2 = 1.1

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3 years ago

A pet store donated a percent of every sale to charity. The total sales were $6600 so the store donated $330. What percent of

xz_007 [3.2K]

Answer:

its 5%

Step-by-step explanation:

6600-5%= 6270

6600-6270= 330

3 0

3 years ago