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3 years ago

Find the slope of a line perpendicular to the given line. x = - 1

Mathematics

1 answer:

kolbaska11 [484]3 years ago

4 0

The slope would be undefined, because it would be going straight vertical.

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Find the perimeter of the polygon. Assume that lines which appear to be tangent are tangent. Round to the nearest tenth if neces

kherson [118]

Answer:

$P=53.6\ units$

Step-by-step explanation:

we know that

The <u><em>Two-Tangent Theore</em></u>m states that if two tangent segments are drawn to one circle from the same external point, then they are congruent

Applying the Two-Tangent Theorem at each vertex of the triangle

The perimeter of the triangle is equal to

$P=2(7.8)+2(8)+2(11)=53.6\ units$

6 0

3 years ago

Jammal spend $66 on supplies to make some woodworking items if he sells his items for $7.25 each how many items does he have to

inna [77]

Answer:

Step-by-step explanation:

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3 years ago

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vovikov84 [41]

1018262910101101 explanation:

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2 years ago

Solve the inequality.<br><br> y−5≥8

mixas84 [53]

Answer:

Y is less than or equal to 13

Step-by-step explanation:

3 0

3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago