Answer:
there is no answer
Step-by-step explanation:
Answer:
The two points solutions to the system of equations are: (2, 3) and (-1,6)
Step-by-step explanation:
These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:
x = 2 and x = -1
Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:
when x = 2 then 
when x= -1 then 
Then the two points solutions to the system of equations are: (2, 3) and (-1,6)
Answer: C
Step-by-step explanation:
This describes an expotential function
At t = 0, P = 70
Therefore, C = 70
P = 70 e^kt
Solve for k by plugging in (4,360)
k = 0.4094
plug in t(7 hours)
70 e^(0.4094*7)
The answer roughly equals C
Answer:
the answer is B
Step-by-step explanation: