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kkurt [141]
2 years ago
9

The charge on an ion is

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
7 0

Answer:

C. Either positive or negative

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Suppose that you are attempting to estimate the annual income of 1700 families. In order to use the infinite standard deviation
andrew-mc [135]

Answer:

Sample size should be less than 85

Step-by-step explanation:

Sample size should be less than 85

Step-by-step explanation:

To use the infinite standard deviation formula, n has to be <= (0.05)(1700)

n <= 85

So the sample size has to be less than 85

In another way too,

n = sample size

N = population size

For population, we multiply correction factor to the infinite standard deviation

F is <= 0.05

n/{N}

n<0.05x1700

n<85

Sample size should be less than 85

7 0
3 years ago
4. Which equation is true?
Pepsi [2]

Answer:

C

Step-by-step explanation:

5+3 = (-1)-(-9)

5+3 =(-1)+9

8 = 8

3 0
3 years ago
Would someone mind answering this for me? Thank you
Naddik [55]

(a) m = \frac{1}{2}

calculate the slope (m) using the ' gradient formula '

m = \frac{(y_{2 - y_{1)} } }{(x_{2 - x _{1)} } }

let (x₁, y₁) = (8, 9) and (x₂, y₂) = ( - 2, 4)

m = \frac{(4 - 9)}{(-2 - 8)} = \frac{-5}{-10} = \frac{1}{2}

(b) y - 9 = \frac{1}{2} (x - 8)

the equation of a line in ' point- slope form ' is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

choose any of the 2 given points for (a, b) → (8, 9)

y - 9 = \frac{1}{2} (x - 8) → " point- slope form"

(c) y = \frac{1}{2} x + 5

the equation of a line in ' slope-intercept form ' is

y = mc + c

where m is the slope and c the y-intercept

expand and simplify the point- slope equation

y - 9 = \frac{1}{2} x - 4

y = \frac{1}{2} x - 4 + 9

y = \frac{1}{2} x + 5 → " slope- intercept form"




6 0
3 years ago
Please helpppppp meeee
yKpoI14uk [10]

Answer:

0.25     Converges

Step-by-step explanation:

First, we need to expand our series so that we get the following:

\sum _{n=1}^{\infty \:}\frac{n}{4^n}+\frac{1}{4^{n+1}}

We can then use the series ratio test on each term. (L < 1 = absolutely convergent)

\sum _{n=1}^{\infty \:}\frac{n}{4^n}

\lim_{n \to \infty} \frac{n}{4^{n}\\} =

⇒  converges

\sum _{n=1}^{\infty \:}\frac{1}{4^n^+1}

\lim_{n \to \infty} \frac{n}{4^{n}^+1\\}

⇒  converges

converges + converges

= converges

~Hope this helps! Once again, sorry if my explanation is a bit confusing~

8 0
3 years ago
1 2 2 4 3 9 4 16 what is the range of the function please help
Ivahew [28]

Answer:

<h2 />

Step-by-step explanation:

x            y

1            2

2           4

3           9

4           16

This sounds like a quadratic equation of f(x)=x^2, thus, the range is:

<h3>R(x): (-∞,+∞)</h3><h3 /><h3>If the function only has these points, then the range is:</h3><h3>R(x): [2]∪[4]∪[9]∪[16]</h3>
3 0
3 years ago
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