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Olegator [25]
3 years ago
12

Please helpppppp meeee

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

0.25     Converges

Step-by-step explanation:

First, we need to expand our series so that we get the following:

\sum _{n=1}^{\infty \:}\frac{n}{4^n}+\frac{1}{4^{n+1}}

We can then use the series ratio test on each term. (L < 1 = absolutely convergent)

\sum _{n=1}^{\infty \:}\frac{n}{4^n}

\lim_{n \to \infty} \frac{n}{4^{n}\\} =

⇒  converges

\sum _{n=1}^{\infty \:}\frac{1}{4^n^+1}

\lim_{n \to \infty} \frac{n}{4^{n}^+1\\}

⇒  converges

converges + converges

= converges

~Hope this helps! Once again, sorry if my explanation is a bit confusing~

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<span>Using the points (2, 45) (4, 143) and (10, 869), we can plug them into the following system of 3 equations using the y = ax^2 + bx + c format:

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Solving the system, we get a = 9, b = -5, and c = 19. Thus the equation is:

c(x) = 9x^2 - 5x + 19

If you have a TI graphing calculator, you can also enter the points by pressing Stat -> Edit and enter (2, 45) (4, 143) and (10, 869) into it. Go back and calculate the QuadReg of the points from the Calc tab and it will give you the same answer.

Now that we know the function that will produce the price of production for any number of calculators, plug in x = 7 and it will give you the price to produce 7 calculators.

c(x) = 9x^2 - 5x + 19
==> c(7) = 9(7)^2 - 5(7) + 19
==> c(7) = 441 - 35 + 19
==> c(7) = 425

Therefore, it costs $425 to produce 7 calculators.

Hope this helps.

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