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Olegator [25]
3 years ago
12

Please helpppppp meeee

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

0.25     Converges

Step-by-step explanation:

First, we need to expand our series so that we get the following:

\sum _{n=1}^{\infty \:}\frac{n}{4^n}+\frac{1}{4^{n+1}}

We can then use the series ratio test on each term. (L < 1 = absolutely convergent)

\sum _{n=1}^{\infty \:}\frac{n}{4^n}

\lim_{n \to \infty} \frac{n}{4^{n}\\} =

⇒  converges

\sum _{n=1}^{\infty \:}\frac{1}{4^n^+1}

\lim_{n \to \infty} \frac{n}{4^{n}^+1\\}

⇒  converges

converges + converges

= converges

~Hope this helps! Once again, sorry if my explanation is a bit confusing~

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soldi70 [24.7K]
1/12c = 0.6

To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).

12(1/12c) = 0.6*12

The 12 cancels out leaving this: 

c  = 0.6 * 12
c = 7.2

If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this: 
6/10 simplifying it becomes, 3/5

3/5 * 12 = 36/5

Now! That was assuming 1/12c was written like this: 
(1/12)c = 0.6

If it was actually written like this: 
1/(12c) = 0.6 then you'll do this. 

Multiply 0.6 by 12c. Which will get you 7.2c. After that you need to get c alone, so you divide both sides by 7.2. Yielding the result: 

1/7.2 = c 

c = 0.1389...


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HACTEHA [7]

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