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2 years ago

What table shows the function y=-2x-8

Mathematics

1 answer:

Zolol [24]2 years ago

4 0

Answer:

Step 1

Swap sides so that all variable terms are on the left hand side.

-2x-8=y−2x−8=y

Step 2

Add 88 to both sides.

-2x=y+8−2x=y+8

Step 3

Divide both sides by -2−2.

\frac{-2x}{-2}=\frac{y+8}{-2}

−2

−2x

−2

y+8

Hint

Undo multiplication by dividing both sides by one factor.

Step 4

Dividing by -2−2 undoes the multiplication by -2−2.

x=\frac{y+8}{-2}x=

−2

y+8

Hint

Undo multiplication.

Step 5

Divide y+8y+8 by -2−2.

x=-\frac{y}{2}-4x=−

−4

Hint

Divide.

Solution

x=-\frac{y}{2}-4x=−

−4

Step-by-step explanation:

yan po sana makatulong

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A 5% destroys solution is given intravenously. Suppose a total of 2.64 L of the solution is given over a 19-hour period. What is

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Answer:

The flow rate is 138.95 mL per hour.

Step-by-step explanation:

We are given the following in the question:

Volume of solution = 2.64 L

1 L = 1000 mL

Volume of solution in mL =

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Time period = 19 hour

Unit rate of flow =

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3 years ago

A angles of an equilateral triangle are congruent. If x represents the measure of the third angle of the triangle, what is x?

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Answer:

Step-by-step explanation:

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All 3 angles have a measure of x

The sum of the 3 angles in a triangle = 180°, this

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3 years ago

Need help ASAP <br> Mathswatch

pshichka [43]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Fernell and Dabney shared the driving

Agata [3.3K]

Answer:

15 hours

Step-by-step explanation:

Given:

Fernell's speed $v_F= 50$ mph

Dabney's speed $v_D= 64$ mph

Denote:

$D_F$ - distance covered by Fernell

$D_D$ - distance covered by Dabney

$t_F$ - Fernell's time

$t_D$ - Dabney's time

1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

$t_F=t_D+3$

2. If Fernell covered 18 miles less than Dabney, then

$D_D-D_F=18$

Use formula $D=t\cdot v$

$D_D=v_D\cdot t_D\Rightarrow D_D=64\cdot t_D\\ \\D_F=v_F\cdot t_F\Rightarrow D_F=50\cdot (t_D+3)$

Subtract from the first equation the second equation and equate it to 18:

$64t_D-50(t_D+3)=18\\ \\64t_D-50t_D-150=18\\ \\14t_D=168\\ \\t_D=12\ \text{hours}$

$t_F=t_D+3=12+3=15\ \text{hours}$

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3 years ago

Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

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6 0

2 years ago