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elena-s [515]
2 years ago
8

What table shows the function y=-2x-8

Mathematics
1 answer:
Zolol [24]2 years ago
4 0

Answer:

Step 1

Swap sides so that all variable terms are on the left hand side.

-2x-8=y−2x−8=y

Step 2

Add 88 to both sides.

-2x=y+8−2x=y+8

Step 3

Divide both sides by -2−2.

\frac{-2x}{-2}=\frac{y+8}{-2}

−2

−2x

=

−2

y+8

Hint

Undo multiplication by dividing both sides by one factor.

Step 4

Dividing by -2−2 undoes the multiplication by -2−2.

x=\frac{y+8}{-2}x=

−2

y+8

Hint

Undo multiplication.

Step 5

Divide y+8y+8 by -2−2.

x=-\frac{y}{2}-4x=−

2

y

−4

Hint

Divide.

Solution

x=-\frac{y}{2}-4x=−

2

y

−4

Step-by-step explanation:

yan po sana makatulong

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3 years ago
1. Segment AE is 7 inches and AH is 7^/3 inches. What is the length of EH? Round to the nearest tenth.
Orlov [11]

Answer:

1.) 9.9

2.) 15.6

Step-by-step explanation:

1.) Consider triangle AEH

AEH is a right angle triangle as ∠AEH = 90°

AH is the hypotenuse of the triangle.

Applying Pythagorean theorem

AE^{2} + EH^{2} = AH^{2}

substituting values as given in the question:

7^{2} +EH^{2}=(7\sqrt{3} )^{2}\\EH^{2}=(7\sqrt{3} )^{2}-7^{2} \\EH^{2}=98\\EH=\sqrt{98}\\EH=7\sqrt{2}

∴ EH≈9.9

2.) Consider triangle CDF

CDF is a right angle triangle as ∠CDF = 90°

CF is the hypotenuse of the triangle.

Applying Pythagorean theorem

CD^{2} + DF^{2} = CF^{2}

substituting values as given in the question:

11^{2} +DF^{2}=(11\sqrt{3} )^{2}\\DF^{2}=(11\sqrt{3} )^{2}-11^{2} \\DF^{2}=242\\DF=\sqrt{242}\\DF=11\sqrt{2}

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3 years ago
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I hope this helps. if not, feel free to leave a feed back.

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