Answer:
20%
Step-by-step explanation:
4/5=.80
1-.80=.20
.20=20%
9514 1404 393
Answer:
7 pizzas
Step-by-step explanation:
For a difference in price of $58 -25 = $33, a customer gets a difference in number of 5 -2 = 3 pizzas. Then a pizza costs $33/3 = $11.
The cost of 2 pizzas is $22, so the delivery charge is $25 -22 = $3.
For $80, after subtracting the $3 delivery charge, $77 goes to the cost of pizzas. For that amount, $77/$11 = 7 pizzas will be delivered.
The best estimate would be 2,000 but, the original answer is 2,023
Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence
. - Equally as likely to be a boy or a girl, hence
.
The probability of one of each is P(X = 1), hence:


0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377