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Digiron [165]
2 years ago
13

N is the in center of △ABC. Use the given information to find NS. NQ=2x NR=3x−2

Mathematics
1 answer:
kramer2 years ago
4 0

Given that N is the incenter of △ABC, NS = 4.

<h3>What is the Incenter of a Triangle?</h3>
  • The incenter of a triangle is the point of concurrency of the three angle bisectors of a triangle.
  • The perpendicular distances from each sides of the triangle to the incenter are equal.

Given the image where:

NQ = 2x

NR = 3x − 2

NQ = NR = NS (equidistant from the incenter)

Thus:

2x = 3x - 2

  • Add like terms

2x - 3x = -2

-x = -2

x = 2

NQ = NS = 2x

  • Plug in the value of x

NS = 2(2)

NS = 4

Therefore, given that N is the incenter of △ABC, NS = 4.

Learn more about the incenter on:

brainly.com/question/1831482

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The symbol ⊕ is used to denote exclusive or, so p ⊕ q ≡ (p v q) ^ ~ (p ^ q).
Elan Coil [88]

I'll use text forms of the logical symbols because copying/pasting on mobile is annoying.

⊕ = XOR

∨ = OR

∧ = AND

~ = NOT

↔ = IFF (meaning "if and only if")

→ = IMP (short for "implies")

and for logical equivalence I'll use a regular equal sign.

Then

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(a) By definition of XOR, we have

p XOR p = (p OR p) AND NOT (p AND p)

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and this is tautologically FALSE.

(b) To rewrite XOR, first distribute the NOT over the AND using DeMorgan's law:

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Then we can interchange the AND and ORs using their respective distributive properties. That is,

p XOR q = (p OR q) AND (NOT p OR NOT q)

= (p AND (NOT p OR NOT q)) OR (q AND (NOT p OR NOT q))

= ((p AND NOT p) OR (p AND NOT q)) OR ((q AND NOT p) OR (q AND NOT q))

Both (p AND NOT p) and (q AND NOT q) are tautologically FALSE, so the truth value of either OR depends only on the other statements, so we have

p XOR q = (p AND NOT q) OR (q AND NOT p)

Recall the definition of IFF:

p IFF q = (p IMP q) AND (q IMP p)

Also recall that IMP is logically equivalent to

p IMP q = p OR NOT q

Then we have

p IFF q = (p OR NOT q) AND (q OR NOT p)

so that its negation is

NOT (p IFF q) = NOT ((p OR NOT q) AND (q OR NOT p))

= NOT (p OR NOT q) OR NOT (q OR NOT p)

= (NOT p AND q) OR (NOT q AND p)

The statements in bold match, so p XOR q is indeed equivalent to NOT (p IFF q).

3 0
3 years ago
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3 years ago
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7/10

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