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pickupchik [31]
3 years ago
7

The distance from Mars to the Sun is 1.416×10^8 miles. The distance from Earth to the Sun is 9.296×10^7 miles. How many more mil

es is the distance from Mars to the Sun than the distance from Earth to the Sun?
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

4.864*10^7\ miles

or

48,640,000\ miles

Step-by-step explanation:

we know that

To determine how many more miles is the distance from Mars to the Sun than the distance from Earth to the Sun, subtract the distance from Earth to the Sun from the distance from Mars to the Sun

Let

x ----> the distance from Mars to the Sun in miles

y ----> the distance from Earth to the Sun in miles

Find out

(x-y)

we have

x=1.416*10^8\ miles

y=9.296*10^7\ miles

we need to adjust the powers of 10 in the 2 numbers so that they have the same index

Multiply  the distance from Earth to the Sun by 10/10

y=9.296*10^7(\frac{10}{10})=0.9296*10^8\ miles

Find out the difference

(x-y)=1.416*10^8\ miles-0.9296*10^8\ miles=0.4864*10^8\ miles

Multiply by 10/10

0.4864*10^8(\frac{10}{10})=4.864*10^7\ miles

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Use the given information to find the minimum sample size required to estimate an unknown population mean μ.
larisa86 [58]

Answer:

The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean is:

 CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

 MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $569

MOE = $140

Confidence level = 95%

<em>α</em> = 5%

Compute the critical value of <em>z</em> for <em>α</em> = 5% as follows:

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*Use a <em>z</em>-table.

Compute the sample size required as follows:

MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}  

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Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

4 0
3 years ago
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