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2 years ago

13

Each day, Valerie charges her lunch account for her lunch. If the cost of lunch is $3, then by how much has her lunch account be

en impacted over a period of 15 days?

1 answer:

Anuta_ua [19.1K]2 years ago

6 0

Answer:

$45

Step-by-step explanation:

$3 times 15 days = $45

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Which unit rate is the lowest price per ounce? Choice A: 15 ounces of chocolate chips for $2.49 Choice B: 20 ounces of chocolate

iris [78.8K]

2.49/15 = 0.166
3.32/20 = 0.166

they both cost the same per oz

3 0

3 years ago

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The graph below shows a line of best fit for data collected on the average heights of children.

a_sh-v [17]

Answer:

A. 41

Step-by-step explanation:

Look at the number 6 and follow the line until it shows you the number, which 41

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2 years ago

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Use the net to find the surface area of the cylinder. 6ft and 7ft

earnstyle [38]

Answer:

A. 84 pi feet^2

Step-by-step explanation:

So the lateral area is the rectangular piece on the net

In order for it to be an actual cylinder the 2 circles are congruent

Therefore the radi, area, circumference ect.. are the same.

So the only missing measurement we need to find the lateral area is the length of the rectangular piece

If you visualize a cylinder, the rectangular piece goes around the perimeter/circumference of the circle

So that means that the length of the rectangle is the circumference of the circle

Circumference = 2*pi*r

2 * pi * 6

= 12 pi

Then 7*12 pi

=84 pi

So the lateral area is 84 pi

:0

8 0

2 years ago

How many different three-digit numbers can be formed using the digits 1 comma 2 comma 9 comma 6 comma 4 comma 3 comma and 8 wit

lozanna [386]

Answer:

129 468

Step-by-step explanation:

I'm not sure if you're supposed to reuse the same numbers just in a different Three digit number. Or if you're supposed to use the number one time and one time only. But if not here's there's some numbers that you could use

He basically all You have to do Is take the numbers and turning them into three digit numbers Without repetition.

Hope this helps you!

Also it's saying that 664 is not allowed Because it they are reusing the six When there's no Extra six to use. So remind you not to use the same number twice!

3 0

3 years ago

Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago