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3 years ago

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On a coordinate plane, a curved line crosses the y-axis at (0, 1), crosses the x-axis at (.25, 0), turns at point (2, negative 3

), and crosses the x-axis (3.75, 0). What is the range of the function on the graph?

1 answer:

jenyasd209 [6]3 years ago

7 0

Answer:

All numbers greater than or equal to -3.

Step-by-step explanation:

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Answer:

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djyliett [7]

Answer:

$3$ and perpendicular

Step-by-step explanation:

It's important to remember that equations of lines are always set up in the format of $y=mx+c$ .

$y$ is the $y$ value, $m$ is the gradient/slope, $x$ is the $x$ value and $c$ is the y-intercept.

Therefore, we must always rearrange our line equations so that $y$ is the subject.

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We rearrange to make $y$ the subject:

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Then, we divide both sides by 6 to have the $y$ isolated:

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So here, the slope is $-\frac{1}{3}$ .

So, the negative reciprocal of that would be $3$ because we inverse the sign (the negative becomes positive) and the fraction is flipped to create $\frac{3}{1}=3$ .

So, the perpendicular slope is $3$ .

In the second question, we have two equations. They both need to be rearranged to isolate the $y$ .

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Look at the slopes of the two equations. If you look carefully, you will see that they are inverse of each other (one is positive and one is negative) and if you imagine $4 = \frac{4}{1}$ , the fraction is flipped.

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2 years ago

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I'll do this step-by-step. Note, ratios are basically division signs.

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Use y=mx+b. This is for slope. If you're given a coordinate such as (3,2) think of "dibble and then shoot". Go right three and up two. Hope this helps :)

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