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vitfil [10]
3 years ago
7

In the first two hockey games of the year, Rodayo played 1 1/2 periods and 1 3/4 periods. How many periods in all did he play? P

lease help
Mathematics
2 answers:
Talja [164]3 years ago
7 0

Answer:

Rodayo played 3 1/4 periods in all

Step-by-step explanation:

Anastasy [175]3 years ago
4 0

Answer:

3 1/4, or 4 periods if it’s rounded (which I think not)

Step-by-step explanation:

First, add the wholes 1 + 1 = 2

Next, add the fractions 1/2 + 3/4

Taking from that, you would have 13/4 all together, turning the wholes into fractions.

If your looking for decimals, it’s 3.25

You find the total by adding fractions

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Simplify by combining like terms 5 4/7i+4 3/5i
Arturiano [62]
Simplify by combining the real and imaginary parts of each expression

Answer: 356i/35
7 0
3 years ago
What is the next number in the sequence 0,2,6,12
pashok25 [27]

Answer:

20

Step-by-step explanation:

We are adding 2

0+2 =2

Then 4

2+4 = 6

Then 6

6+6=12

Then we would add 8

12+8 = 20

7 0
3 years ago
Read 2 more answers
The correlation analysis assumes that the measurements have a bivariate normal distribution in the population. Select all of the
RoseWind [281]

Answer:

A. True

B. True

C. False

D. False

E. False

F. False

G. True

Step-by-step explanation:

Select all of the features that define a bivariate normal distribution.

<em>(this means that we select only those that are properties of the bivariate normal distribution)</em>

A. Bell-shaped probability distribution in two dimensions rather than one

<em>TRUE  because any combination of the two is still normal Z(x,y)=aX+bY</em>

B. A relationship between X and Y that is not linear

<em>TRUE The contours of the distribution are ellipses.</em>

C. The presence of outliers

<em>FALSE possible, but not always.</em>

D. Either X or Y has a decidedly skewed distribution

<em>FALSE normal distributions are symmetric</em>

E. A relationship between X and Y that is linear

<em>FALSE see answer to B</em>

F. A cloud of points that is funnel shaped (wider at one end than the other)

<em>FALSE normal distributions are symmetric</em>

G. The frequency distributions of X andY separately are normal

TRUE For example, in <em>Z(x,y)=aX+bY, putting a or b=0 means that X and Y separately are normal.</em>

4 0
3 years ago
With bases V1, V2 , V3 andw1, w2 , W3, suppose T(v1) = w2 and T(v2) = T(v3) = w1 + w3 . T is a linear transformation. Find the m
Roman55 [17]

Answer:

See picture and explanation below.

Step-by-step explanation:

With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.

A is defined as T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)] denotes the vector of coordinates of T(v_i) respect to the basis (we can apply this definition because forms a basis for the domain of T).

The vector of coordinates can be computed in the following way: if T(v_i)=a_1w_1+a_2w_2+a_3w_3 then [T(v_i)]=(a_1,a_2,a_3)^t.

Note that we have all the required information: T(v_1)=0w_1+1\cdot w_2+0w_3 then [T(v_1)]=(0,1,0)^t

T(v_2)=T(v_3)=1\cdot w_1+0w_2+0w_3 hence [T(v_2)]=[T(v_3)]=(1,0,0)^t

The matrix A is on the picture attached, with the multiplication A(1,1,1).

Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:

T(v_1+v_2+v_3)=T(v_1)+T(v_2)+T(v_3)=w_2+w_1+w_1=w_2+2w_1  

In this last case, we can either use the linearity of T or multiply by A.

4 0
3 years ago
0.04x -0.06y=0.48<br> 0.08x-0.11 y=0.92
UkoKoshka [18]

Answer:

0.04x -0.06y=0.48

x = 1.5y + 12

0.08x-0.11 y=0.92

x = 1.375y + 11.5

Hope this helps!

6 0
3 years ago
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