Answer:
u put the algebraic like terms together whether they add or subtract each other
What you can do in this case is the following rule of three to find the result:
1 light year ---> 5.88 * 10 ^ 12 miles
3.2 * 10 ^ 2 light year ---> x
Clearing x we have:
x = ((3.2 * 10 ^ 2) / (1)) * (5.88 * 10 ^ 12)
x = 1.88 * 10 ^ 15 miles
answer:
In scientific notation, approximately it is 1.88 * 10 ^ 15 miles
Answer:
The required probability is 4/7.
Step-by-step explanation:
The sample space for the experiment is: { BB, BR, RB, RR }
The outcome of the event we require is: { BR, RB }
The probabilities for each outcome is given as:
BB: 3/7 x 2/6 = 1/7
BR: 3/7 x 4/6 = 2/7
RB: 4/7 x 3/6 = 2/7
RR: 4/7 x 3/6 = 2/7
Adding the probabilities we have:
{ BR, RB} = 2/7 + 2/7 = 4/7
That's it!
The answer is g^-1= x^2/2 + 1/2
