The straight line graph is the one that shows a direct, proportional relationship.
Answer:
The answer to your question is letter D
Step-by-step explanation:
We know that the sum of the internal angles in a triangle equals 180°.
So, B = 30°, C = 90° and A = ?
A + B + C = 180°
Substitution
A + 30 + 90 = 180
Solve for A
A = 180 - 30 - 90
A = 180 - 120
A = 60°
To find "b". use the trigonometric function sine
sin B = 
sin B x hypotenuse = Opposite side
Opposite side = sin 30 x 10
Opposite side = 0.5 x 10
Opposite side = b = 5.0
To find "a" use the trigonometric function cosine
Cos A = adjacent side / hypotenuse
Adjacent side = a = cos A x hypotenuse
Adjacent side = a = cos 60 x 10
a = 0.866 x 10
a = 8.66
To find this answer, you need to find a common denominator. A common denominator is when the number on the bottom of two fractions is the same. The easiest was to do this is to first multiply the two denominators, then multiply the numerator (or top number) by the opposite denominator. This sounds complicated, but it's pretty simple. Here's the equation written out. (I hope this helps!)
4*8 = denominator for both numbers.
8*1 = numerator for the first number
4*1 = numerator for the second number.
This should give you the fractions with common denominators, 8/32 and 4/32. Then, to compare the fractions, just see which numerator is larger. In this case, 8 is larger than 1 which shows that 1/4 is greater than 1/8.
I hope this made sense. There's more than one way to solve these problems, so comment below if you would like me to explain it differently and I'll get back to you as soon as I can! :)
Answer:
A'(7,-3)
Step-by-step explanation:
We were given the coordinates, A(-7,3) of quadrilateral ABCD and we want to find the image of A after a reflection across the x-axis followed by a reflection in the y-axis.
When we reflect A(-7,3) across the x-axis we negate the y-coordinate to obtain: (-7,-3).
When the image is again reflected in the across the y-axis, we negate the x-coordinate to get (--7,-3).
Therefore the coordinates of A' after the composed transformation is (7,-3).
