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fomenos
3 years ago
5

A lawn had a length of 10 feet and a width

Mathematics
1 answer:
BigorU [14]3 years ago
5 0
36 square feet
10 plus 10 is 20 plus 8 plus 8 is 16
so 20+16 =36
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A regular polygon is inscribed in a circle of radius 11 cm. Calculate the perimeter of the polygon to the nearest tenth if the p
Oduvanchick [21]
I believe the answer is 176cm cause if the radius is 11 the diameter is 22 so I hope this helps!
7 0
3 years ago
Please help. I don’t know the answer.
atroni [7]
(y^12)/5

9/45=1/5
x^5/x^5=1
y^16/y^4=y^12
4 0
2 years ago
Read 2 more answers
What is y=2x-3 y=-3/4x-1/4 with work shown please help
makvit [3.9K]
2X-3 = -3/4x -1/4
Add 3 on both sides: 2X = -3/4x + 2.75
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8 0
3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
Please help me with these 6 through 10 :)
drek231 [11]
6.) constant = 75

7.) open sentence = 6 + 22 = 28

8.) equation = 17 + b = 47

9.) solution = when x + 37 = 62, x = 25
3 0
3 years ago
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