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aev [14]
3 years ago
5

Can someone help on thiissssds

Mathematics
2 answers:
guapka [62]3 years ago
7 0

Answer:

B

Step-by-step explanation: we can rewrite these equations first

3x + 21 = 23 + 4x

3x = 2 + 4x

x = -2

4y - 28 = 3y - 23

4y = 3y + 5

y = 5

( - 2 , 5 )

Ahat [919]3 years ago
6 0

Answer:

\huge\boxed{\sf Solution Set = \{(-2,5)\}}

Step-by-step explanation:

<u>Given equations:</u>

-4x + 3y = 23 ---------------------------(1)

x - y = -7 ---------------------------------(2)

Multiply Eq(2) by 3

3(x - y) = -7 * 3

3x - 3y = -21 ---------------------------(3)

Add Eq (1) and (3)

-4x + 3y + 3x - 3y = 23 + (-21)

Cancel out 3y

-4x + 3x = 23 - 21

- x = 2

Or

x = -2

<u>Finding y:</u>

Put x = -2 in Eq. (2)

-2 - y = -7

Add 2 to both sides

-y = -7 + 2

-y = -5

Divide both sides by -1

y = 5

So,

Solution Set = {(x,y)} = {(-2,5)}

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

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