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gizmo_the_mogwai [7]
2 years ago
13

X+2y=3 3y+5y=7 I dont know

Mathematics
1 answer:
Lena [83]2 years ago
8 0

Answer:

Step-by-step explanation:

3y+5y=8y

8y=7(divide 8 in both sides to get y)

y=7/8

x+2y=3...but we already know the value of y, so substitute 7/8 to y

x+2(7/8)=3

x+14/8=3

x=3-14/8

=1.25

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X=9/64^7

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A jar of peanut butter and a jar of jam cost $10.20 in total. the jar of peanut butter costs $10.00 more than the jar of jam. ho
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Well this is pretty simple. So the first thought is that the peanut butter would be 10$ and the jam would be 0.20$, however, the peanut butter would not be 10$ more. Instead, subtract the 10$ from the total, which gives you 0.20$, and then divide that by two. Now you have 0.10$ for each, along with another 10$ for the peanut butter. The peanut butter would be $10.10, and the jam would be 0.10$ (that's pretty cheap!).
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3 years ago
When x=2 and y=4, by how much does the value of 4x^2 - y exceed the value of 3x^2 - 3y​
kakasveta [241]

Step-by-step explanation:

4(2)² - 4 =

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2 years ago
Complete the equation of the graphed linear function in point-slope form.
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3 years ago
PLEASE HELP I AM SO CONFUSED
Natasha2012 [34]

Answer:

a)  h(3) = 9

b)  h(0) = 6

c)  h(6) = 4

Step-by-step explanation:

Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.

Given piecewise function:

\sf h(x)=\begin{cases}\sf \dfrac{x^2-36}{x-6} &\textsf{if }x\neq  6\\\\\sf 4 & \textsf{if }x=6\end{cases}

Therefore, the function has two definitions:

  \sf h(x)=\dfrac{x^2-36}{x-6} \quad \textsf{when x does not equal 6}

  \sf h(x)=4 \quad \textsf{when x equals 6}

<u>Part (a)</u>

h(3) means to substitute x = 3 into the function.

As <u>x does not equal 6</u>, substitute x = 3 into the <u>first piece of the function</u>:

\begin{aligned}\sf \implies h(3) & =\sf \dfrac{(3)^2-36}{(3)-6}\\\\ & = \sf \dfrac{9-36}{-3}\\\\ & = \sf \dfrac{-27}{-3}\\\\ & = \sf 9\end{aligned}

<u>Part (b)</u>

h(0) means to substitute x = 0 into the function.

As <u>x does not equal 6</u>, substitute x = 0 into the <u>first piece of the function</u>:

\begin{aligned}\sf \implies h(0) & =\sf \dfrac{(0)^2-36}{(0)-6}\\\\ & = \sf \dfrac{0-36}{-6}\\\\ & = \sf \dfrac{-36}{-6}\\\\ & = \sf 6\end{aligned}

<u>Part (c)</u>

h(6) means to substitute x = 6 into the function.

As <u>x equals 6</u>, then use the <u>second piece of the function</u>:

\sf \implies h(6)=4

Learn more about piecewise functions here:

brainly.com/question/11562909

brainly.com/question/28151925

7 0
11 months ago
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