All categories

1 year ago

Help me i’m struggllinbggg with this

Mathematics

1 answer:

Olenka [21]1 year ago

8 0

The opposite angles of a parallelogram are congruent, so you have to set the values of each angle equal to each other and solve for x.

(10x-19)° = (7x+23)°
-7x -7x
3x-19 = 23
+19 +19
3x = 43
÷3 ÷3
x = 43

Then, substitute the value of x back into the equations.
(10x-19)°
(10(14)-19)°
(140-19)°
121°

(7x+23)°
(7(14)+23)°
(98+23)°
121°

You might be interested in

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

2 years ago

What is located at (–2, –2)?

tatuchka [14]

Answer:

B. The post office

youre welcome!

5 0

2 years ago

Are they inverse ? please hurry

ddd [48]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

∠WXY and ∠ZXY are adjacent angles. What equation must always be TRUE? m∠WXY=m∠ZXY

Hitman42 [59]

Answer:

m∠WXY+m∠ZXY=m∠WXZ

Step-by-step explanation:

You don't know the angles to be congruent (equal measures), complementary (measures add to 90 deg), or supplementary (measures add to 180 deg); all you know is that they are adjacent, so the sum of the measures of the two smaller angles equals the measure of the larger outer angle.

Answer: m∠WXY+m∠ZXY=m∠WXZ

3 0

3 years ago

What is the sum of (2x3 - 5) + (x3 + 3) ?

Gennadij [26K]

Use a calculator and try to put. All in order

4 0

2 years ago