Show me the steps to solve and the solution y-2>1/2(x-2)

1 answer:

4 0

y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1

Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

Add 4 to both sides: 2y > x + 2

Div. both sides by 2: y > (1/2)x + 1 (answer)

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I need help working this out

Leona [35]

I think in this situation the best method would be a guess and check. You know that there are 8 dimes more than there are nickels. So just keep increasing each number by one until you reach $1.40. If there were 9 dimes and 1 nickels it would add up to $0.95. If there were 10 dimes and 2 nickels, it would add up to $1.10. If there were 11 dimes and 3 nickels, it would add up to $1.25. If there were 12 dimes and 4 nickels, it would add up to $1.40. So your answer is 12 dimes and 4 nickels.

I hope this helped!

8 0

3 years ago

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Given a = 4, b = -2 and c = 8, evaluate ab - bc. -24 -4 8

Mrac [35]

(4*-2)-(-2*8)=
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8 0

3 years ago

A sandwich shop offers a choice of 4 types of bread, 8 types of meat, and 4 types of cheese. How many different sandwiches could

Fantom [35]

4x8x4=

128

...............

7 0

3 years ago

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If the tan of angle x is twenty two fifths and the triangle was dilated to be two times as big as the original, what would be th

8_murik_8 [283]

Answer:

22/5

Step-by-step explanation:

The sides increase but in the same ratio,

Hence opposite/adjacent for image and pre image is the same ratio.

Therefore, tanX is 22/5

6 0

3 years ago

Simplify the quotient: y= 2x^2+10x-28/x^2-49 divided by 2x-4/x+7

devlian [24]

$\textit{difference of squares} \\\\ (a-b)(a+b) = a^2-b^2 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2x^2+10x-28}{x^2-49}\div \cfrac{2x-4}{x+7}\implies \cfrac{2x^2+10x-28}{x^2-49}\cdot \cfrac{x+7}{2x-4} \\\\\\ \cfrac{2(x^2+5x-14)}{\underset{\textit{differenc of squares}}{x^2-7^2}}\cdot \cfrac{x+7}{2x-4}\implies \cfrac{2(x^2+5x-14)}{(x-7)~~\begin{matrix} (x+7) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} x+7 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{2(x-2)}$

$\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x^2+5x-14)}{x-7}\cdot \cfrac{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x-2)}\implies \cfrac{x^2+5x-14}{x-7}\cdot \cfrac{1}{x-2} \\\\\\ \cfrac{~~\begin{matrix} (x-2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(x+7)}{x-7}\cdot \cfrac{1}{~~\begin{matrix} x-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{x+7}{x-7}=y$

4 0

2 years ago