A circle has diameter 18 inches, and a chord is 14 inches long. What is the distance in inches from the chord to the center of t he circle, to the nearest hundredth?
1 answer:
Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
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A tangent forms a right angle with the centre of circle at the point it touches the circumference. i.e. OAB = 90 degrees If AOB = 55 degrees, then ABO = 90 - 55 = 35 degrees