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malfutka [58]
3 years ago
5

The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu

late the shaded area, in the square inches, of the diagram

Mathematics
1 answer:
mart [117]3 years ago
5 0

Answer:

The shaded area is 23\ in^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

so

A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})

Calculate the shaded area

Remember that

3^{2}=9\\ 2^{2}=4

substitute

A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}

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Answer:

260 gallons

Step-by-step explanation:

Hope it's correct

8 0
3 years ago
Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2.<br><br> Is -3 the correct answer?
Ket [755]
We're given the algebraic expression 2x^2 - 2z^4 + y^2 - x^2 + z^4

By hypothesis, x = -4, y = 3 and z = 2

Let's replace each letter by its given value:

2x^2 - 2z^4 + y^2 - x^2 + z^4
2(-4)^2 - 2(2)^4 + (3)^2 - (-4)^2 + (2)^4
(2*16) - 2*16 + 9 - 16 + 16
32 - 32 + 9 - 16 + 16
9

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Hope this helps! :D
6 0
3 years ago
Someone please tell me what this is, the question is what is the slope of this line ?
AnnyKZ [126]

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
-13 = 2x +7x -4 help please
Gnoma [55]

Answer:

Just solve for x:

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4 0
3 years ago
Read 2 more answers
Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

1\frac{1}{8}\\\\=\frac{9}{8}\ miles

Width of rectangular lot is given by

\frac{9}{10}\ mile

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


3 0
3 years ago
Read 2 more answers
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