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marta [7]
3 years ago
11

Use addition to solve the linear system of equations. Include all of your work in your final answer.

Mathematics
1 answer:
love history [14]3 years ago
4 0
We have that
<span>x - y = 4-------> multiply by -1-----> -x+y=-4-----> equation 1
x+ 2y = 4------> equation 2

add equation 1 and equation 2
-x+y=-4
x+2y=4
-----------------
0+3y=0-----> y=0
x+2y=4------> x+0=4------>x=4

the solution is the point (4,0)</span>
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Which of the following is the solution to the inequality below ? -6/5(4-x)&lt;_-4(X+1/2)
LuckyWell [14K]

Answer:

The answer is the option D

x\leq 7/13

Step-by-step explanation:

we have

-\frac{6}{5}(4-x)\leq -4(x+\frac{1}{2})

Multiply by -5 both sides

6(4-x)\geq 20(x+0.5)\\24-6x\geq20x+10\\24-10\geq 20x+6x\\14\geq 26x

Rewrite

26x\leq 14\\x\leq 14/26\\ x\leq 7/13


7 0
3 years ago
2.Pleas can someone answer!
kenny6666 [7]

Answer: A, A, C

Step-by-step explanation:

Educated Guess because none of them are going to be zero so it's either A or C but the point has a negative y so to plug it all in all of them have to be negative ex. -1 + -1 + -1 =-3

the x is -1 so both have to be negative in order to get -3

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3 years ago
What are the equations for these graphs
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4 0
3 years ago
Please help! Due soon
sesenic [268]

Answer:

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Step-by-step explanation:

7 0
3 years ago
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
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