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omeli [17]
2 years ago
7

Which is the better buy twelve cans for7 dollors or 6 cans for 4 dollors

Mathematics
2 answers:
choli [55]2 years ago
7 0

I will say 12 cans for 7$ because if you buy a second pair of 12 cans it will cost 14 but if you buy 6 cans for 4 dollars but another pair would be 8$,but i also depends on how much cans you will need ;)

Hope this helps :)

ValentinkaMS [17]2 years ago
6 0

The better buy should be buy twelve cans for 7 dollors

Given that,

  • twelve cans for7 dollors or 6 cans for 4 dollors.

Based on the above information, the calculation is as follows:

The first option is

= 7\div 12

= $0.58

The second option

= 4\div 6

= $0.67

Learn more: brainly.com/question/16911495

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Solve each compound inequality. Graph your solutions.<br> 5 + m &gt; 4 or 7m&lt; -35
Yuliya22 [10]

Answer:

Solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality 5 + m > 4\: or\: 7m< -35

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m

So, solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

5 0
2 years ago
Weights of American adults are normally distributed with a mean of 180 pounds and a standard deviation of 8 pounds. What is the
ahrayia [7]

Answer:

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 180, \sigma = 8

What is the probability that a randomly selected individual will be between 185 and 190 pounds?

This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So

X = 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 180}{8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 185

Z = \frac{X - \mu}{\sigma}

Z = \frac{185 - 180}{8}

Z = 0.63

Z = 0.63 has a pvalue of 0.7357

0.8944 - 0.7357 = 0.1587

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

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Answer:

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Step-by-step explanation:

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Answer:

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