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Talja [164]
3 years ago
9

JK:ST is 2:1 and the length of JN is 6/2. What is the length of SW ?

Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

3/2

Step-by-step explanation:

2:1 => difference of 1/2

6/2 is also 3

Following the same pattern SW = 3 x 1/2

also 3/2

Hope this helps!

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How do i solve this
aleksandr82 [10.1K]
Replace g for -2 and h for 5.

(2(-2) + 9(5) -5) - (6(-2) - 4(5) +2)

Taking this one at a time,
2(-2) = -4, and 9(5) = 45.
6(-2) = -12 and -4(5) = -20

(-4 + 45 - 5) - (- 12 - 20 +2)

Let’s distribute the negative symbol to the right side.

(-4 + 45 - 5) + (12 + 20 - 2)

Then, we solve!
(-4 + 40) + (12 + 18)

(36) + (30)

= 66!
8 0
3 years ago
Read 2 more answers
The width of a rectangle is 2 meters less than its length, and the perimeter is 32 meters. Find the length and width of the rect
cupoosta [38]
The perimeter is equal to 2(width) + 2(length). let's call the width w and the length L.

so 32 = 2w + 2L
the width is given as 2 meters less than the length, so w = L - 2

32 = 2(L - 2) + 2L
32 = 2L - 4 + 2L
32 = 4L - 4
36 = 4L
9 = L

so our length is 9 meters.

w = L - 2
w = 9 - 2
w = 7

so our width is 7 meters.
3 0
4 years ago
MATH MATH MATH MATH HeLp
Mila [183]

Answer:

B is the correct option dear .

Step-by-step explanation:

Good luck ^_^

6 0
3 years ago
Read 2 more answers
How do i find BC?<br><br> Khan Academy
Brrunno [24]

Answer:

using cos=adjacent/hypotenuse

Step-by-step explanation:

in this case cos(60)=x/4√3

x=cos(60)*4√3

x=3.46

6 0
3 years ago
find the product with the exponent in the simplest form. Then, identify the values of x and y. 6^1/3 * 6^1/4 = 6^x/y
mr Goodwill [35]
<span>6^1/3 * 6^1/4 = 6^x/y

The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.

6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y
 
So the product would be 6^7/12
x = 7
y = 12</span>
6 0
3 years ago
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