Find a substance half-life in days. round your answer to the nearest tenths
2 answers:
A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
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Height of triangle is 5 cm
To find:
Value of 'a' and 'b'
Steps:
To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,
A² + B² = C²
Now to find the value of 'b', i will use law of cosine,
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Answer:
The midpoint is (2.5,-6) or written as a fraction (, -6)
Step-by-step explanation:
Answer:
The mean, μ is 2.5063 and
The standard deviation, σ = 2.0499 × 10⁻²
Step-by-step explanation:
Here we have
and
10% have length < 2.48 in while
5% have length > 2.54 in
and
From the z score table
Critical z at 10% to the left = -1.282
Critical z at 5% to the right = 1.645
Therefore, the equations become
-1.282σ = 2.48 - μ → μ -1.282σ = 2.48
1.645σ = 2.54 - μ → μ + 1.645σ = 2.54
Solving the above equations gives
The mean, μ = 2.5063 and
The standard deviation, σ = 2.0499 × 10⁻².
Answer:
The cosine of ∠V is of 0.74.
Step-by-step explanation:
Relations in a right triangle:
The cosine of an angle is given by the length of the adjacent side divided by the length of the hypotenuse.
XW = 65, WV = 97, and VX = 72.
, and thus, this is a right triangle.
What is the value of the cosine of ∠V to the nearest hundredth?
The hypotenuse is the largest side, that is, WV = 97.
The adjacent side of angle V is VX = 72. So
The cosine of ∠V is of 0.74.