Find a substance half-life in days. round your answer to the nearest tenths
2 answers:
A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
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Answer:
Price per television =38.30
Step-by-step explanation:
Number of units sold in one week =230-3x
Price of one unit =x
Total money produced in one week =x(230 - 3x)
(Here it doesn't matter total money is taken for a week or day because after differentiating and equating to zero that factor disappear )
Differentiate total amount with respect to x.
Now equate it equal to zero to get extremum.
230-6x=0
Then, x = 38.30
Answer:
a. The slope of a line parallel to the given line is 1
b. A point on the line parallel to the given line, passing through (−4, 2), is (1,7)
c. The slope of the line perpendicular to the given line is -1
d. A point on the line perpendicular to the given line, passing through (−4, 2), is (3,-5)
Step-by-step explanation:
The equation of the line in Slope-intercept form is:
Where m is the slope and b is the y-intercept.
a. For the line
You can identify that:
By definition, two lines are parallel if they have the same slope. Then, the slope of a line parallel to the given line is:
b. The equation of the line in Point-slope form is:
Where m is the slope and () is a point of the line.
Given the point (-4,2), substitute this point and the slope of the line into the equation:
Give a value to "x", substitute it into this equation and solve for "y":
For :
Then, you get the point (1,7)
c. The slopes of perpendicular lines are negative reciprocals, then the slope of a line perpendicular to the given line is:
d. Given the point (-4,2), substitute this point and the slope of the line into the equation:
Give a value to "x", substitute it into this equation and solve for "y":
For :
Then, you get the point (3,-5)