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12345 [234]
2 years ago
7

Please Help! Gabe Amodeo a nuclear physicists needs 80 liters of a 30% acid solution. He currently has a 20% and a 60% solution

How many liters of each does he need to make the needed 80 liters of 30% acid solution?
Mathematics
2 answers:
adelina 88 [10]2 years ago
6 0
He needs 6 litres of the 20% and 2 litres of the 60% a simple trial and error method will do in this type of equation
Nataly [62]2 years ago
3 0
Let x be the number of liters needed from the first acide concentration (20%)
Let y be the number of liters needed from the first acide concentration (60%)

We know at the end we will have:
x+y = 80 ; we also know that:
20%(x) + 60%(y) = 30%(80) OR 0.2x + 0.6y = 0.3(80) = 2x+6y=240

Hence we have :
x+y = 80
2x+6y = 240
Solving this system of 2 equations give: x = 60 and y = 20
In short you need to mix 60 litres at 20% and 20 liters at 60%

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3 years ago
2.25k - 20 = 6.5k + 14<br><br><br> plsssssssssssss
Pani-rosa [81]

Answer:

k=-8

Step-by-step explanation:

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3 years ago
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Tonya has a small picture with a length of inches. She wants to enlarge the picture by a factor of 7 and frame it. Which of the
Elena L [17]
Enlarge the picture 7 times by inches
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3 years ago
PLEASE HELP WORTH 16 POINTS WILL REPORT LINKS
Igoryamba

Answer:

Angle A = 30.8

Angle B = 33.2

Step-by-step explanation:

180 - 116 = 64  

This means that the other two angles need to add up to 64.

I just plugged in numbers until it worked.

I got that x = 14.6

2x + 4

2(14.6) + 4

29.2 + 4

33.2

3x - 13

3(14.6) - 13

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30.8

Those are your angles. To make sure they are correct you just need to add up all the angles and make sure that they equal to 180.

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6 0
2 years ago
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you send 12 photos to a company that makes personalized wall calendars the company enlarges the photos and inserts one for each
Assoli18 [71]

Answer:

15 inches

Step-by-step explanation:

We have that,

Length of the photo = 4 inches and Width of the photo = 6 inches

Also, the width of the image on the calendar = 10 inches

Let, the length on the image of the calendar = x inches.

Since, the ratio of the photo and its image will remain same, we get,

\frac{4}{6}=\frac{10}{x}

i.e. x=\frac{60}{4}

i.e. x = 15

Hence, the length of the image of the photo on the calendar is 15 inches.

3 0
3 years ago
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