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12345 [234]
3 years ago
7

Please Help! Gabe Amodeo a nuclear physicists needs 80 liters of a 30% acid solution. He currently has a 20% and a 60% solution

How many liters of each does he need to make the needed 80 liters of 30% acid solution?
Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0
He needs 6 litres of the 20% and 2 litres of the 60% a simple trial and error method will do in this type of equation
Nataly [62]3 years ago
3 0
Let x be the number of liters needed from the first acide concentration (20%)
Let y be the number of liters needed from the first acide concentration (60%)

We know at the end we will have:
x+y = 80 ; we also know that:
20%(x) + 60%(y) = 30%(80) OR 0.2x + 0.6y = 0.3(80) = 2x+6y=240

Hence we have :
x+y = 80
2x+6y = 240
Solving this system of 2 equations give: x = 60 and y = 20
In short you need to mix 60 litres at 20% and 20 liters at 60%

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Polynomial division (-12m^2-49mn-44n^2)/(-3m-4n)
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First factor -12m^n - 49mn - 44n^2 to get -(4n+3m)(11n + 4m) then the equation would be:
-(3m + 4n)(4m + 11n) / (-3m - 4n)
Then, cancel out the like terms and the final answer would be
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7 0
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Julli [10]

Answer:

14 ounces of blue paint

Step-by-step explanation:

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To solve this problem we can make a proportion:

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To solve the proportion you have to cross multiply:

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I hope this helps :)

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2 years ago
Use radical notation to rewrite the expression 144 1/2
andrew-mc [135]
144^{\frac{1}{2}} = \sqrt{144}
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The answer to this problem is 45
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Read 2 more answers
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