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alekssr [168]
3 years ago
13

Please help I need this answered. Find x and explain. I’ll give brainliest.

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

I dont know what you mean by find x but if you want to find x you have to isoulat the varubal.

Step-by-step explanation:

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What is the unknown factor 9Xp= 45
Airida [17]
5 is your missing factor because 9*5=45 btw dont use x for multiplication use this *

3 0
3 years ago
What's the hight of a million pennies
TiliK225 [7]

The thickness of a brand new US penny that hasn't been
worn down is 1.52 millimeters.

If you have a million pennies, there are many ways to arrange them.
You can pile them all in one pile, or shovel them into many piles, or
stack them up in any number of stacks up to a half-million stacks
with two pennies in each stack, or try somehow to stack them all up
in one stack that's a million thicknesses high.

Any stack with 'n' pennies in the stack is  1.52n millimeters high.

If you somehow succeed in stacking all million of them in one stack,
then the height of that stack would be . . .

       (1,000,000) x (1.52 mm) =  1,520,000 millimeters
                                                         152,000 centimeters
                                                             1,520 meters
                                                               1.52 kilometers

                                            (about 59,842.5 inches
                                                          4,986.9 feet
                                                         1,662.3 yards
                                                               7.56 furlongs
                                                            0.944 mile
                                                                  all rounded)

3 0
3 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
3 years ago
Which of the following pairs of values for x and y would justify the claim that the two triangles are congruent? x = 3, y = 11 x
irinina [24]

Answer:

A

Step-by-step explanation:

just got it right

7 0
3 years ago
Is x=7 a solution to the equation x-5-3(x+2)?<br> Fill in the blanks to answer the question.
Anuta_ua [19.1K]

Answer:

1) 2=27

2) x= -11/2

3) no

Step-by-step explanation:

8 0
2 years ago
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