Ask question

Ask question

All categories

3 years ago

5

Why are there so many moose attacks

2 answers:

boyakko [2]3 years ago

7 0

Answer:

Moose attacks spike in September and October which is mating season, and early Spring also due to young calves being raised. Many moose attacks on humans are actually provoked from dogs. Moose hate dogs and wolves, and become extremely aggressive by their presence, especially at a dog that barks.

lorasvet [3.4K]3 years ago

4 0

Answer: h

Step-by-step explanation:

Female moose who have young calves get protective when humans do come too close. Same as with males but who are in heat or protective of their territory.

You might be interested in

Octavian became the emperor of Rome in 27 B.C. He ruled until his death in A.D. 14. How long did he rule as emperor? (Hint: Reme

raketka [301]

40 years, a simple google search would give you the answer.

5 0

3 years ago

Read 2 more answers

What is the exponential form for 7^√x^3

Semenov [28]

Answer:

The exponential form of this would be (7x)^3/2

Step-by-step explanation:

The square root symbol is the same as writing raised to the 1/2. So we can rewrite the equation as:

[(7x)^1/2]^3

Then we can multiply the two exponents in this case giving us

(7x)^3/2

7 0

3 years ago

Read 2 more answers

You roll a number cube twice. What is the probability of rolling a 2 first and then rolling an odd number?

nevsk [136]

So i believe the answer is d) 1/9

3 0

3 years ago

emily is buting gifts for 20 people at work.The boxes for the gifts are 6 inches long,6 inches wide ,and 6 inches high .How much

kvasek [131]

Answer:

360 inches or 30 feet

Step-by-step explanation:

6x3=18

18×20=360 inches

or...

360÷12=30 to get amount in feet.

3 0

3 years ago

A cylindrical can, open at the top, is to hold 840 cm3 of liquid. Find the height and radius that minimize the amount of materia

ycow [4]

Answer:

the radius of the base is equal to $x=2\sqrt[3]{\frac{105}{\pi } }$

And the height is equal to:

$y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }$

Step-by-step explanation:

We write the volume function

$f(x,y)=840=\pi x^{2} y$ where x is the radius of the base and y is the height of the cylinder

$y=\frac{840}{\pi x^{2} }$

The surface of a cylinder is given by

$S(x)=\pi x^{2} +2\pi xy=\pi x^{2} +\frac{1680}{x}$ on the interval from 0 to infinity

We now determine the critical values by differentiating and making the equation equal to 0

$f'(x)=2\pi*x- \frac{1680}{x^{2}} =\frac{2\pi x^{3}-1680}{x^{2} } =0$

This equation have 2 complex solutions and one real solution

$x=2\sqrt[3]{\frac{105}{\pi } }$

For x=0 and infinity the equation goes to infinity also so the radius of the base is equal to $x=2\sqrt[3]{\frac{105}{\pi } }$

And the height is equal to:

$y=\frac{840}{\pi (2\sqrt[3]{\frac{105}{\pi } })^{2} }$

$y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }$

7 0

3 years ago