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Alina [70]
2 years ago
13

A large bottle of juice contains 500 ml a This use medium bottle contained 70% as much juice as the large bottle how many millil

iters of juice are in the medium bottle
Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0
Charlidamelio is overrated
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Find the value of x. WILL GIVE BRAINLIEST!!!
Readme [11.4K]

Answer: x = 16

Step-by-step explanation:

24 + 2 + 4x = 90

26 + 4x = 90

4x = 64

x = 16

6 0
3 years ago
Points A, R and G are points of tangency. Find the perimeter of ∆NET below.
Paha777 [63]

Answer:

\small\mathfrak\red{here \: is \: your \: solution..} \\  \\ we \: know \: that \: tangent \\ from \: a \: same  point \: are \: equal \\  \\ tr = 9 | an = 7 |  eg = 5 \\  \\ tr = ta | an = gn | eg = re \\  \\ ta = 9 |  gn =7 | re = 5 \\  \\ hence \: perimeter \:  = 2(9 + 7 + 5) \\  \\ perimeter = 42 \:  \\  \\ \huge\mathfrak\purple{hope \: it \: helps...}

6 0
3 years ago
Which equation is a step in solving the equation 5 - 3x + 2 = 19?
Leni [432]

Answer:

D. 5-3x = 17

Step-by-step explanation:

The step carried out was subtracting 2 from both sides.

5 - 3x + 2 = 19 \\ 5 - 3x + 2 - 2 = 19 - 2 \\ 5 - 3x = 17

4 0
3 years ago
if trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A’lie
maria [59]

Answer:

<em>Answer: (second option) (-4,1)</em>

Step-by-step explanation:

<u>Transformations of Points and Shapes</u>

The image shows a trapezoid ABCD where point A has coordinates (-4,1).

The following transformations are performed:

Reflection over the y-axis: If a point (x,y) is reflected over the y-axis, it becomes (-x,y). Thus point A becomes A'=(4,1)

Reflection over the x-axis: If a point (x,y) is reflected over the x-axis, it becomes (x,-y). Thus point A' becomes A''=(4,-1)

Rotation 180°: If a point (x,y) is rotated 180°, it becomes (-x,-y). Thus point A'' becomes A'''=(-4,1)

Answer: (second option) (-4,1)

5 0
2 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
2 years ago
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