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guajiro [1.7K]
2 years ago
11

Bonjours je n'arrive pas a répondre a cette question pouvez vous m'aider SVP ? merci d'avance

Mathematics
1 answer:
worty [1.4K]2 years ago
5 0
5/(Q+1) est la plus petite
You might be interested in
The ratio of two numbers is 4:5 if the larger number is 300 what is the smaller number​
yaroslaw [1]

Answer:

The smaller number is 240.

Step-by-step explanation:

The question says that the larger number is 300, so 5 has to be 300.

4:5

?:300

You can use cross-multiplication or find the scale factor to find the answer.

Cross-multiplication:

4 × 300 ÷ 5 = 240

Finding the scale factor:

300 ÷ 5 = 60

4 × 60 = 240

The smaller number is 240.

6 0
2 years ago
There are 180 cars in a parking lot.30% are red .How many red cars are there ?
den301095 [7]

54 red cars, sorry cant explain, need points urgently, CHEERIO!

6 0
3 years ago
How many questions would I have to miss on a 25 question test to get 88% ?
N76 [4]
Let's start with the question, how many questions do you need to get 88%?

so were are looking for
?/25 = 88% and 88% is also 0.88 so we can multiply 25 by 0.88

we get 22


But this doesn't here. the question asks us how many mistakes do you need. you can just subtract 22 from 25

25-22= 3
you need 3 misses to get 88%
7 0
3 years ago
I'd seriously appreciate it if anyone could help! :) I'll give Brainliest! Please show your work.
san4es73 [151]

The depth of a river changes after a heavy rainstorm. Its depth, in feet, is modeled as a function of time, in hours

y is the depth in feet and x is the time in hours

From the table we can see that

In 9 hours, the depth is 18 feet

In 18 hours , the depth is 21 feet

(9,18 ) and  (18,21)

Average rate of change = \frac{y_2-y_1}{x_2-x_1}

= \frac{21-18}{18-9}

= \frac{3}{9}

= \frac{1}{3}

the average rate of change for the depth of the river is  \frac{1}{3} feet per hour

8 0
3 years ago
Find the maximum and the minimum value of the following objective​ function, and the value of x and y at which they occur. The f
kumpel [21]

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7):  E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

8 0
3 years ago
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