Question

I need help with this last question !!!

Answer 1

So∠DHG = 7x-42, and since ∠FHC is directly opposite of it, it's the same value, 7x-42.

∠AGH should equal ∠CHF since they're both on parallel lines and line EF intersects them.

Therefore, ∠AGH =∠FHC:

3x-10=7x-42 (Subtract 7x and -10)

-4x=-32

x=8

∠DHG should be 8°