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Dominik [7]
2 years ago
7

 PLEASE HELP ILL GIVE BRAINLIESTTTT

Mathematics
1 answer:
zhenek [66]2 years ago
5 0
Yes they are similar they just need to me flipped than you can flip them again
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Cube root of b to the 12 power​
kvv77 [185]

\sqrt[3]{b^{12}}=\sqrt[3]{(b^4)^3}=b^4

6 0
3 years ago
Is 11/20 greater than a half
Rainbow [258]
Yes... a half is equal to 10/20 and 11/20 is greater than 10/20 so 11/20 is greater than a half
8 0
3 years ago
Read 2 more answers
Simplify the expression –3(x 3)2 – 3 3x. what is the simplified expression in standard form?
777dan777 [17]

-3(x^{2} +5x+10) is the standard form of the given expression

The given expression is:

=-3(x+3)^{2} -3+3x\\\\=-3*(x^{2} +2*3*x+3^{2} )-3+3x\\\\=-3x^{2} -3*6x-3*9-3+3x\\\\=-3x^{2} -18x-27-3+3x\\\\=-3x^{2} -15x-30\\\\=-3(x^{2} +5x+10)

This is the standard form of the given expression.

Learn more about Simplifying expression here brainly.com/question/723406

#SPJ4

7 0
2 years ago
Which ecpression is equivalent to sqrt 8x^7y^8?
mars1129 [50]

Domain:\ x\geq0\ \wedge\ y\in\mathbb{R}

\sqrt{8x^7y^8}=\sqrt8\cdot\sqrt{x^7}\cdot\sqrt{y^8}=\sqrt{4\cdot2}\cdot\sqrt{x^6\cdot x}\cdot\sqrt{y^{4\cdot2}}\\\\=\sqrt4\cdot\sqrt2\cdot\sqrt{x^6}\cdot\sqrt{x}\cdot\sqrt{(y^4)^2}=2\sqrt2\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\cdot y^4\\\\=2y^4\sqrt2\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}=2y^4\sqrt{2x}\cdot x^3\\\\=\boxed{2x^3y^4\sqrt{2x}}

Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\ for\ a\geq0

7 0
4 years ago
Write the rational number as a decimal - 3/11​
oksano4ka [1.4K]

Answer

0.27

Step-by-step explanation:

3 divided by 11

= 0.27

this is it I believe

8 0
3 years ago
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