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pishuonlain [190]
3 years ago
11

Alguien sabe este trabajo es para hoy :’(

Mathematics
2 answers:
Kazeer [188]3 years ago
6 0
I would be able to help but I need it to be in English
Inga [223]3 years ago
4 0

no psss ya valio madres

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If Gigi and Bella combined their weekly pay they would make $55.
Anastasy [175]
Answer:Gigi’s weekly pay is $30
Bella’s weekly pay is $25

Step 1 Guess:25
Step 2 Add:25+25=50 50+5=55
Step 3 Check:30+25=55
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3 years ago
What is another name for a unit
Korolek [52]

Answer:Group

Step-by-step explanation:

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4 years ago
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Given that cosθ=7/25 , what is sinθ ?
OLga [1]

Answer:

sin  θ = 24/25.

Step-by-step explanation:

Cos θ = 7/25 so we have a right triangle with adjacent side = 7 and hypotenuse = 25.

So the opposite side = sqrt ( 25^2 - 7^2) ( By Pythagoras)

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Find two numbers with a sum of 20 and a difference of 14
sergey [27]

Find two numbers with a sum of 20 and a difference of 14


Make two equations

X+Y=20

X-Y=14


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2x=34


Now divide 2 both sides to get x alone

2x/2=34/2


X=17


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17+y=20


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4 0
3 years ago
The question is Fiona's swimming pool is a right rectangular prism. It holds 137 1/2 cubic feet of water. The length of the pool
cricket20 [7]

Answer:

The width is 4 feet

Step-by-step explanation:

Yes, I might be able to answer it! Hello there!

In this question, we are asked to calculate the height of a pool which has a shape of right rectangular prism.

The key to solving this problem is simply by knowing the formula for the volume of a right rectangular prism.

Mathematically the volume V is w * h * l where w , h and l are the width, height and length respectively.

Now let’s input these values and get what the height of the pool is.

It would be easier if you had the measurements are in decimals;

137 1/2 becomes 137.5

6 1/4 becomes 6.25

5 1/2 becomes 5.5

kindly note the fraction 1/2 is 0.5 in decimals while the fraction 1/4 is 0.25 in decimals

So now let’s compute the height;

137.5 = w * 6.25 * 5.5

w = 137.5/(6.25 * 5.5)

w = 137.5/(34.375)

w = 4 feet

8 0
3 years ago
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