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DedPeter [7]
3 years ago
5

Hi I need help. I will also tell you this so you don't end up doing it. So the question about Toby is not a problem for you to d

o so don't do it. If your here to help, I'm here to give.

Mathematics
1 answer:
mote1985 [20]3 years ago
8 0

5. 25 = x + 3

It is a one step equation. You just need to subtract 3 on both sides to get x.

6. 2b - 7 = 15

This is a two step equation. You need to add 7 on both sides and then divide both sides by 2 to get b.

7. 10m = 90

Finally, this is a one step equation. You need to divide both sides by 10 to find m.

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Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps bel
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He made a mistake in step #2. It seemed to be a trivial mistake because it involved signs, but it still had a great impact. Since step#2, his solution was already wrong.

Instead of
(-1)²-4(2)(-6) = 1 + 48 = 49

What he did is
(-1)²-4(2)(-6) = -1 + 48 = 47
4 0
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P(5,2) = 5!/3! = 20

in 20 ways you can give medals

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3 years ago
To divide using a model, which of the following are true? Select all that are correct.
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Im srry can you give me the answers for the question

Step-by-step explanation:

Plz so I can help you

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3 years ago
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Alex17521 [72]
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3 0
3 years ago
Solve the triangle A = 2 B = 9 C =8
VARVARA [1.3K]

Answer:

\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}

Then, given the sides a=2, b=9, and c=8.

\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}

For B:

\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}

3 0
1 year ago
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