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3 years ago

Geometry help please

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

x
------- = 19.32
50

x
(50) ----- = 19.32 (50)
50

x = 966 cm^3

Hope this helps! :)

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Can somebody please help me with this?

ser-zykov [4K]

Answer:

d fasho

Step-by-step explanation:

8 0

2 years ago

The sum of 43.9 and a number is 49.65, as shown below. What number should go in the box to complete the addition problem? 43.9 p

Ber [7]

43.9 + n = 49.65
43.9-43.9 + n = 49.65 -43.9
n = 5.75

6 0

3 years ago

Evaluate the expression. [(3–5)(34)]3 1 Innermost group, apply the product of powers: [3–1]3 2 Apply the power of a power: 3–3 3

Otrada [13]

Answer:

x=27

Step-by-step explanation:

To evaluate the expression: $[(3^{-5})(3^4)]^3$

Step 1: Innermost group, apply the product of powers ( $a^x \times a^y =a^{x+y}$

Therefore:

$(3^{-5})(3^4)=3^{-5+4}=3^{-1}$

We then have:

$=[3^{-1}]^3$

Step 2: Apply the power of a power

$[3^{-1}]^3=3^{-1 \times 3} =3 ^{-3}$

Step 3: Apply the negative exponent

$3 ^{-3} =\dfrac{1}{3^3}$

Step 4: Simplify

$\dfrac{1}{3^3}=\dfrac{1}{27}$

Therefore, the value of x in the simplified expression is 27.

4 0

3 years ago

If Eric can paint $3$ cars in $4$ hours and $2$ trucks in $5$ hours, then how long, in hours, would it take him to paint $4$ car

deff fn [24]

Answer:

47/6

Step-by-step explanation:

Given that :

Time taken to paint 3 cars = 4 hours

Time taken to paint 2 trucks = 5 hours

How long will it take him to paint 4 cars and a truck

If 3 cars = 4 hours ;

Then ;

1 car = (4/3)hours

If 2 trucks = 5 hours

Then;

1 truck = (5/2) hours = 2 1/2 hours

Time required To paint 4 cars :

4 × (4/3) = 16/3 hours

Time required to paint 1 truck :5/2 hours

Total time required :

(16/3 + 5/2) = (32 + 15) / 6 = 47/6

3 0

3 years ago

there are 11 members on a city council at a recent city council meeting, 4 of the council members voted in favor of a budget inc

ololo11 [35]

We have 11 members at the city council meeting, 4 voted in favour of a budget increase.

The possible groups of council members who could have voted in favour can be found using the combination formula which is used when we want to group items, in this case, we are grouping people.

Here is the formula;

Where n = Total members on the city council = 11

and r = members that voted in favour = 4

We will then solve this to be

$\begin{gathered} \frac{11!}{(11-4)!4!} \\ =\frac{11\times10\times9\times8\times7!}{7!\times4\times3\times2\times1} \\ =11\times10\times3 \\ =330 \end{gathered}$

This implies that there are 330 possible groups of council members who could have voted in favour.

ANSWER: 330

7 0

1 year ago