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charle [14.2K]
2 years ago
9

Solve the following application problem. Be sure to show your system of equations and the steps to solve the problem.

Mathematics
1 answer:
ololo11 [35]2 years ago
6 0

Answer:

  • boat: 6 mph
  • current: 2 mph

Step-by-step explanation:

The relationship between time, speed, and distance is ...

  speed = distance/time

For boat speed b and current speed c, the speed downstream is ...

  b +c = (16 mi)/(2 h) = 8 mi/h

The speed upstream is ...

  b -c = (16 mi)/(4 h) = 4 mi/h

Adding the two equations eliminates the c term:

  2b = 12 mi/h

  b = 6 mi/h . . . . . divide by 2

Solving the second equation for c, we get ...

  c = b -4 mi/h = 6 mi/h -4 mi/h = 2 mi/h

The speed of the boat in still water is 6 mi/h; the current is 2 mi/h.

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B) 5.7 × 107 = 609.9

Step-by-step explanation:

A) 604.2

B) 609.9

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3 years ago
Use substitution to show that 9+ 6(10-7x) is equivalent to 69-42x.
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Martha has 3 cards but she wants more.if she makes 5 cards an hour, how many cards will she have after 6 hours?
Genrish500 [490]

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Step-by-step explanation:


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8 0
3 years ago
Factor by grouping<img src="https://tex.z-dn.net/?f=%284y%5E3%20%2B%2028y%5E2%29%20%2B%20%28y%20%2B%207%29" id="TexFormula1" tit
Inessa05 [86]

We have the following expression given:

(4y^3+28y^2)+(y+7)

We can start selecting as common factor 4y^2 and we got:

4y^2(y+7)+(y+7)

Now we can select y+7 as common factor and we got:

(y+7)\left\lbrack 4y^2+1\right\rbrack

So then our final answer would be:

(y+7)(4y^2+1)

3 0
1 year ago
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