Answer:
10.7 m
Step-by-step explanation:
Given that,
The speed of a sound wave, v = 6,420 m/s
The frequency of the wave, f = 600 Hz
We need to find the wavelength of the wave. We can find it using the below relation as follows :
So, the wavelength of the sound wave is equal to 10.7 m.
Ax^2 = bx Divide by x
ax^2/x = b
ax^(2 -1) = b
ax = b Divide by a
x = b/a
5 <<<< Answer.
x≠0
a≠0
Answer:
Step-by-step explanation:
L
H
S
=
cos
4
x
=
2
cos
2
(
2
x
)
−
1
=
2
(
cos
(
2
x
)
)
2
−
1
=
2
(
2
cos
2
x
−
1
)
2
−
1
=
2
(
4
cos
4
x
−
4
cos
2
x
+
1
)
−
1
=
8
cos
4
x
−
8
cos
2
x
+
2
−
1
=
8
cos
4
x
−
8
cos
2
x
+
1
=
R
H
S
Again
L
H
S
=
cos
4
x
=
2
cos
2
(
2
x
)
−
1
=
2
(
1
−
2
sin
2
x
)
)
2
−
1
=
2
(
1
−
4
sin
2
x
+
4
sin
4
x
)
−
1
=
2
−
8
sin
2
x
+
8
sin
4
x
−
1
=
8
sin
4
x
−
8
sin
2
x
+
1
=
R
H
S
sin
2
x
+
cos
2
x
=
1
cos
2
x
=
1
−
sin
2
x
substitute in the equation as follows
8
cos
4
x
−
8
cos
2
x
+
1
=
8
cos
2
x
(
cos
2
x
−
1
)
+
1
=
8
(
1
−
sin
2
x
)
(
1
−
sin
2
x
−
1
)
+
1
=
8
(
1
−
sin
2
x
)
(
−
sin
2
x
)
+
1
=
8
sin
4
x
−
8
sin
2
x
+
1
Answer:
The correct corresponding part is;
≅ 
Step-by-step explanation:
The information given symbolically in the diagram are;
ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)
Segment 
is congruent to 
( ≅ )
Segment is congruent to ( ≅ )
From which, we have;
∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∠B ≅ ∠D by CPCTC
Segment 
is congruent to 
( ≅ ) by CPCTC
Segment 
bisects 
Segment bisects
Therefore, the correct option is ≅
