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2 years ago

Matt is 54 3/ inches tall. Nancy is 1 3/8 inches taller than Matt and Jane is 1 1/5

Mathematics

1 answer:

gladu [14]2 years ago

4 0

Jane is 8 13/40 inches tall

Given the following:

Height of Matt = 5 3/4 in = 23/4 in

If Nancy is 1 3/8 inches taller than Matt, hence;

Height of Nancy = 23/4 + 11/8 = 46+11/8

Height of Nancy = 57/8 in

if Jane is 1 1/5 inches taller than Nancy, then the height of Jane will be;

Height of Jane = 57/8 + 6/5

Height of Jane = 285+48/40

Height of Jane = 333/40 = 8 13/40 inches

Hence Jane is 8 13/40 inches tall

Learn more on sum here: brainly.com/question/2929160

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3 years ago

Aidan can complete a job in 5 minutes, while Joseph can complete the same job in 15

cluponka [151]

Answer:

10 minutes?

Step-by-step explanation:

Sorry if it is incorrect but what I did was I found the average of 5 minutes and 15 minutes and got 10.

Here's my problem solving explanation:

(5 + 15) / 2 = 10

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3 years ago

Read 2 more answers

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : <em>[ $x^{2}$ + 3x + 3 ] =0 </em>

6 0

4 years ago

What is the outlier of 29, 2, 28, 30, 26, 31

Vladimir [108]

Answer:

Step-by-step explanation:

Given the data : 29, 2, 28, 30, 26, 31

Outlier ;

Lower :Q1 - (1.5 * IQR)

Upper : Q3 + (1.5 * IQR)

Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range

Using calculator :

Q1 = 26

Q3 = 30

IQR = (Q3 - Q1) = 30 - 26 = 4

Lower : 26 - (1.5 * 4) = 20

Upper : 30 + (1.5 * 4) = 36

Hence, the number in the given data which falls outside the range is 2

4 0

3 years ago

Can someone plsss help me?!

MAXImum [283]

Answer:

Angle A is 101

Angle B is 79

Angle C is 83

Angle D is 97

Step-by-step explanation:

Vertical angles are congruent, which applies to C.

Lines are parallel so 79 and angle B are the same

Angle a is 101 because its a supplementary angle

Angle D is 97 because its also a supplementary angle so you subtract 83 from 180.

3 0

2 years ago