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trapecia [35]
2 years ago
14

Pls help fast i will mark brainlyest

Mathematics
1 answer:
salantis [7]2 years ago
6 0
  • m || n
  • Therefore, the alternate angles are equal.
  • Therefore, (7x - 3)° = (6x + 17)°
  • or, 7x° - 6x° = 17° + 3°
  • or, x° = 20°
  • or, x = 20

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>2</u><u>0</u>

Hope you could get an idea from here.

Doubt clarification - use comment section

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4 years ago
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This is my question​
Paraphin [41]

f(x) = (x - 4)(x - 3) \\ g(x) =  \frac{7}{(x - 4)(x + 4)} \\ f.g = (x - 4)(x - 3) \times  \frac{7}{(x - 4)(x + 4)}  \\  (x-4)s \:  are  \: simplified \\ f.g =  \frac{(x - 3) \times 7}{x + 4} =  \frac{7x - 21}{x + 4}  \\ (f.g) (x) =  \frac{7x - 21}{x + 4}

4 0
4 years ago
Find all values of w for which the expression is undefined.
Reika [66]

Hello from MrBillDoesMath!

Answer:

 w = 8, -2



Discussion:

The expression is undefined when the denominator is zero. So when does

w^2 - 6w - 16 = 0?  Let's factor the expression. A little trial and error shows that 8 + (-2) = 6 (the coefficient of w) and 8 * (-2) = -16  (the constant value) so w^2 - 6w -1 6 = (w-8) (w- (-2))  and the expression equals zero when  w = 8 or w = -2


Thank you,

MrB

8 0
4 years ago
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