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Marizza181 [45]
4 years ago
6

Last yearrhere were 1436 8th grade students enrolled at your school. This year there are 1220. What is the percent change in the

number of 8th grade students?
Mathematics
1 answer:
Tanzania [10]4 years ago
8 0

\frac{1220 \times 100}{1436}  \approx 85\% \\ 100\% - 85\% = 15\% \: change

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Solve the problem:
stepan [7]

volume of the box is 675 cubic inches

A machine produces open boxes using square sheets of plastic.

It is a square sheet so length and width are same

Lets assume length as x so width is also x

The machine cuts equal-sized squares measuring 3 inches on a side from each corner of the sheet.

After turning up the sides the height of the box becomes 3 inches

We know the volume of a box formula

Volume = Length * width * height

We know length is  x , width is x  and height = 3

So V = x * x * 3

Given volume = 675 cubic inches

675 = x * x * 3

675 = x^2* 3

Divide by 3 on both sides

225 = x^2

Now we take square root on both sides

x = 15

the length of one side of the open box is 15 inches.



5 0
3 years ago
plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
3 years ago
PLEASE HELP ITS GEOMETRY ILL GIVE BRAINLIEST
Rom4ik [11]
Pretty certain it would be the first answer - X = 6 square root of 2
Y = 6
3 0
3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0
3 years ago
Please help me, I really need help. I will mark brainliest answer!!
masha68 [24]
So, let's list the facts:
1) In a week, the eagle eats 3.85 kilograms
2) there are 7 days in a week
3) on each day, the eagle eats the same amount.
This means that in order to find out how much was eaten on each day, we need to divide the whole week's food by the number of days in a week:

3.85/7= 0.55

(3.85=3.5+0.35 and 5*7=55, so   (3.5+0.35)/7=0.5+0.05=0.55

Every day the eagle eats 0.55 kilograms of meat!
6 0
3 years ago
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