Answer:
value of a.b = -4
Step-by-step explanation:
We need to find a.b
a= 4i-4j
b = 4i+5j
We know that i.i =1, j.j=1, i.j =0 and j.i=0
a.b = (4i-4j).(4i+5j)
a.b = 4i(4i+5j)-4j(4i+5j)
a.b = 16i.i +20i.j-16j.i-20j.j
a.b = 16(1) +20(0)-16(0)-20(1)
a.b = 16 +0-0-20
a.b = 16-20
a.b =-4
So, value of a.b = -4
The maximum units is 200 and , Total revenue is $8,000
<u>Step-by-step explanation:</u>
Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:
We have following function as 
. Let's differentiate this and equate it to zero to find value of x for which the function is maximum!
⇒
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , Value of function at x=200 is :
⇒ 
⇒ 
⇒ 
Therefore , The maximum units is 200 and , Total revenue is $8,000
Answer:
No Solution
Step-by-step explanation:
6 - 3x = 4 - x - 3 - 2x (Given)
6 - 3x = -1 -3x (combine like terms)
7 (addition)
The x cancels each other out so no solution.
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
Subtract g(x) from f(x): (x²+3x-1)-(x³+4x²+1)=-x³-3x²+3x-2
C is the correct answer.
