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german
2 years ago
6

Pls help will give brainliest

Mathematics
2 answers:
BaLLatris [955]2 years ago
6 0

Answer:

247 ft is the correct answer

charle [14.2K]2 years ago
5 0
The answer is d im not 100 percent sure have a nice day sorry if I’m wrong
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Levart [38]
You dived 4,005/16

then you will get your answer
4 0
3 years ago
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use distributive property to simplify the expression 3 (8x + 2y) I need help with my algebra homework someone please help.
inysia [295]

6 \times (4 \times x + y)
4 0
3 years ago
Find the smallest multiple of 15 such that each digit of the multiple is either 0 or 4
SCORPION-xisa [38]
The answer is 4440.  You can determine this by using your rules of divisibility.  We know that is must end in a 0 or 5 to be divisible by 5 and that the sum of the digits must be divisible by 3 in order to divide by 3. One or two 4's together are not divisible by 3.  Three 4's are, but it must end in 0 to be divisible by 5 as well.


5 0
3 years ago
Twice the sum of four and x is three less than x.
aliya0001 [1]

Answer:

-11

Step-by-step explanation

Condition:

2(4+x)=x-3

8+2x=x-3

Combining similar terms

8+3=x-2x

11=-x

OR

x=-11

7 0
3 years ago
it takes someone 15 minutes to prepare 3 1/4 cups of juice how many hours would it take to prepare 32 1/2 cups of juice​
wariber [46]

\bf \begin{array}{ccll} minutes&\stackrel{juice}{cups}\\ \cline{1-2} 15&3\frac{1}{4}\\\\ x&32\frac{1}{2} \end{array}\implies \cfrac{15}{x}=\cfrac{3\frac{1}{4}}{32\frac{1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{3\cdot 4+1}{4}}{\frac{32\cdot 2+1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{13}{4}}{\frac{65}{2}}

\bf \cfrac{15}{x}=\cfrac{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 65 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{15}{x}=\cfrac{1}{10}\implies 150=x\leftarrow \begin{array}{llll} \textit{150 minutes or}\\\\ \textit{2 hours and a half} \end{array}

4 0
3 years ago
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