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DIA [1.3K]
2 years ago
8

Which of the following is not a type of biodiversity?.

SAT
1 answer:
geniusboy [140]2 years ago
8 0

Answer:

Explanation:

what are the options ?

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If the fraction with numerator the square root of x to the fifth power, end root, and denominator the cube root of x to the four
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The answer can be obtained using a calculator.

It corresponds to a notable identity

sin (45) =   \sqrt{2}/ 2

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Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM
Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

<em>#include <cmath></em>

<em>#include "pppm_tip4p.h"</em>

<em>#include "atom.h"</em>

<em>#include "domain.h"</em>

<em>#include "force.h"</em>

<em>#include "memory.h"</em>

<em>#include "error.h"</em>

<em>#include "math_const.h"</em>

<em />

<em>using namespace LAMMPS_NS;</em>

<em>using namespace MathConst;</em>

<em />

<em>#define OFFSET 16384</em>

<em />

<em>#ifdef FFT_SINGLE</em>

<em>#define ZEROF 0.0f</em>

<em>#define ONEF  1.0f</em>

<em>#else</em>

<em>#define ZEROF 0.0</em>

<em>#define ONEF  1.0</em>

<em>#endif</em>

<em />

<em>void PPPMTIP4P::init()</em>

<em>{</em>

<em>  // TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms</em>

<em />

<em>  if (force->newton == 0)</em>

<em>    error->all(FLERR,"Kspace style pppm/tip4p requires newton on");</em>

<em />

<em>  PPPM::init();</em>

<em>}</em>

<em />

<em>void PPPMTIP4P::particle_map()</em>

<em>{</em>

<em>  int nx,ny,nz,iH1,iH2;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))</em>

<em>    error->one(FLERR,"Non-numeric box dimensions - simulation unstable");</em>

<em />

<em>  int flag = 0;</em>

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;</em>

<em>    ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;</em>

<em>    nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;</em>

<em />

<em>    part2grid[i][0] = nx;</em>

<em>    part2grid[i][1] = ny;</em>

<em>    part2grid[i][2] = nz;</em>

<em />

<em>    if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||</em>

<em>        ny+nlower < nylo_out || ny+nupper > nyhi_out ||</em>

<em>        nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;</em>

<em>  }</em>

<em />

<em>  int flag_all;</em>

<em>  MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);</em>

<em>  if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");</em>

<em>}</em>

<em>void PPPMTIP4P::make_rho()</em>

<em>{</em>

<em>  int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;</em>

<em>  FFT_SCALAR dx,dy,dz,x0,y0,z0;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];</em>

<em>  for (i = 0; i < ngrid; i++) vec[i] = ZEROF;</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double *q = atom->q;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = part2grid[i][0];</em>

<em>    ny = part2grid[i][1];</em>

<em>    nz = part2grid[i][2];</em>

<em>    dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;</em>

<em>    dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;</em>

<em>    dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;</em>

<em />

<em>    compute_rho1d(dx,dy,dz);</em>

<em />

<em>    z0 = delvolinv * q[i];</em>

<em>    for (n = nlower; n <= nupper; n++) {</em>

<em>      mz = n+nz;</em>

<em>      y0 = z0*rho1d[2][n];</em>

<em>      for (m = nlower; m <= nupper; m++) {</em>

<em>        my = m+ny;</em>

<em>        x0 = y0*rho1d[1][m];</em>

<em>        for (l = nlower; l <= nupper; l++) {</em>

<em>          mx = l+nx;</em>

<em>          density_brick[mz][my][mx] += x0*rho1d[0][l];</em>

<em>        }</em>

<em>      }</em>

<em>    }</em>

<em>  }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

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According to the frustration aggression theory, which of the following is likely to occur when Simon gets frustrated with his to
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According to the frustration-aggression theory, the action that is likely to occur when Simon gets frustrated with his toilet training is that Simon bites his mother

<h3>What is the Frustration Aggression Theory?</h3>

'This refers to the psychodynamic approach that is used to analyze certain behaviors that are exhibited when a person is frustrated by a situation.

Hence, we can see that from the complete information, Simon is given toilet training by his mother and he is an unruly child and based on the fact that he does not get it right, he would bite his mother out of frustration.

Read more about frustration-aggression theory here:

brainly.com/question/13122345

#SPJ1

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