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2 years ago

What does x - 9 multiplied by x + 4 equal

Mathematics

1 answer:

GarryVolchara [31]2 years ago

5 0

Answer:

x^2 - 5x -36

Step-by-step explanation:

multiply x-9 by x to get x^2 -9x. multiply x-9 by 4 to get 4x-36. add these two together to get x^2 - 9x + 4x - 36. simplify to get x^2 - 5x -36

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Solve each equation. Show all steps 4) -8(-6-5k)=-232

Lubov Fominskaja [6]

the answer is k=4.6. hope this helps

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3 years ago

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Westkost [7]

Answer:

Step-by-step explanation:

2(x)+4=16

2(6)+4=16

12+4=16

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3 years ago

What is the equation of the line that passes through the point (6,3) has a slope of -1/3

DerKrebs [107]

Answer:

y = -1/3x + 5

Step-by-step explanation:

y = mx + b

so y = 3, x = 6, m = -1/3

then 3 = (-1/3)6 + b

3 = -2 + b

b = 5

so y = -1/3x + 5

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2 years ago

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Irina18 [472]

Answer:

7:1

Step-by-step explanation:

There are two cubes, one with 14 cm and one with 2 cm. 14:2 is equal to 7:1.

4 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago