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3 years ago

Pls pls help me please!!!!

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

Answer:

Move 6.2 units up

Step-by-step explanation:

(-5.4, 6.2)

The first coordinate is the x coordinate

Positive x moves to the right, negative x moves to the left

Move 5.4 units to the left

The second coordinate is the y coordinate

Positive y moves to up, negative y moves down

Move 6.2 units up

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Plz help plz help I need help

gulaghasi [49]

Answer:

153 ? im not sure srry if wrong

Step-by-step explanation:

20 + 7 = 27

180- 27 = 153

6 0

2 years ago

Read 2 more answers

What can you say about the graph of the function below? Check all that apply.

maw [93]

B y-intercept is (0,1)

5 0

3 years ago

A card is drawn at random out of a well-shuffled deck of 52 cards. Find the probability of drawing a six comma seven comma or e

Rina8888 [55]

Answer: $\frac{3}{13}$ , or ~23.07%

Step-by-step explanation:

There are 52 cards in your average deck.

For this question, you need the numbers of the cards in the deck. There are four of each number from 2 through 10, and four aces, jacks, queens, and kings.

Considering there are four 6s, four 7s, and four 8s, there are 12 cards that fit the description.

Divide 12 by the total number of cards in the deck, 52, to get your answer.

8 0

3 years ago

alani wants to buy a $360 bicycle. she is considering two payment options the image shows option A which consists of making an i

Nataliya [291]

for A)

if she has $ for the downpayment of $70

for B)

360-70+290

290/ 5=58

amount paid = 290-58(#month)

a=290-58m

ANSWER

A= -58m+290

8 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago