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Tom [10]
2 years ago
10

alt="\sqrt{x} ^{2}-\sqrt{27}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Lynna [10]2 years ago
5 0

Answer:

x -   3\sqrt{3}

Study hard!

Brainliest please thank you!

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Can someone please answer this
vlada-n [284]

Answer: 292

Step-by-step explanation: because you have to add every angle on the shape even the ones you cant see

3 0
3 years ago
If x is increased by 25% then, by what % is x² increased
Alinara [238K]

By <em>analytical</em> methods and <em>algebraic</em> handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

<h3>How to determine the percentage increase rate </h3>

In this case we have a <em>linear</em> variable x, whose increase is described by the following expression:

y = x · (1 + r/100)     (1)

Where r is the <em>increase</em> rate.

If we square (1), then we find that:

y² = x² · (1 + r/100)² = (1 + r'/100)     (2)

Where r' is the <em>equivalent increase</em> rate.

(1 + r/50 + r²/10000) = (1 + r'/100)

r'/100 = r/50 + r²/10000

r' = r/2 + r²/100

If we know that r = 25, then the equivalent increase rate is:

r' = 25/2 + 25²/100

r' = 18.75

By <em>analytical</em> methods and <em>algebraic</em> handling and on the basis that x is increased by 25 %, we conclude that the variable x² is increased by 18.75 %.

To learn more on percentages: brainly.com/question/14979505

#SPJ1

5 0
1 year ago
What is the area of trapezoid ABCD ? Enter your answer as a decimal or whole number in the box. Do not round at any steps. units
lidiya [134]

Answer:

37.5 sq. units.

Step-by-step explanation:

The coordinate of vertices of trapezoid ABCD are given,

From the diagram it is clear the area of ABCD = \frac{1}{2}\times AB \times (AD + BC) {Since, AD ║ BC and AB is the perpendicular distance between the parallel lines }

Now, AB = \sqrt{(- 3 - 1)^{2}+ (2 - 5)^{2}  } = 5 units

AD = \sqrt{(- 3 - 0)^{2}+ (2 - (-2))^{2}  } = 5 units

Again, BC = \sqrt{(1-7)^{2}+ (5 - (-3))^{2}  } = 10 units

Therefore, the area of trapezoid ABCD = \frac{1}{2} (10 + 5) \times 5 = 37.5 sq. units. (Answer)

We know, that the distance formula between two points (x_{1}, y_{1}) and  (x_{2}, y_{2}) is  

\sqrt{(x_{1} - y_{1} )^{2} + (x_{2} - y_{2} )^{2}  }.

7 0
3 years ago
Add the following fractions by drawing them 3/8 +1/3​
antiseptic1488 [7]

answer:

\sf \dfrac{17}{24}

step-by-step explanation:

\sf \dfrac{3}{8} +\dfrac{1}{3}

the largest multiple of 8 and 3 is 24, make the denominator same

\sf \dfrac{3(3)}{8} +\dfrac{1(8)}{3}

expand

\sf \dfrac{9}{24} +\dfrac{8}{24}

simplify, join both fractions

\sf \dfrac{17}{24}

8 0
2 years ago
Read 2 more answers
Kayla, Devon and Maggie are working on translating verbal expressions into algebraic
Ksenya-84 [330]

9514 1404 393

Answer:

  4√x -7

Step-by-step explanation:

Four times the square root of x is written 4√x. Seven less than that is found by subtracting 7:

  4\sqrt{x}-7

5 0
3 years ago
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