<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%5E%7B2%7D-%5Csqrt%7B27%7D" id="TexFormula1" title="\sqrt{x} ^{2}-\sqrt{27}"

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Tom [10]

2 years ago

alt="\sqrt{x} ^{2}-\sqrt{27}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Lynna [10]2 years ago

5 0

Answer:

$x - 3\sqrt{3}$

Study hard!

Brainliest please thank you!

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Find exact values for sin θ and cos θ if tan θ = -√3 and θ terminates in Quadrant II.

vivado [14]

Hello :
<span>tan θ = -√3
sin</span>θ = √3/2 1/2
cosθ = -1/2

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2 years ago

Chanelle deposits $7,500 into the bank. She does not withdraw or deposit money for 6 years. She earns 6% interest during that ti

koban [17]

Answer: a. $2700

b. $10200

Step-by-step explanation:

a. The interest she would have earned at the end of the 6 years can be gotten using the formula

= PRT/100

= $7500 × 6% × 6

= $7500 × 6/100 × 6

= $7500 × 0.06 × 6

= $2700

b. Her balance when she wants to withdraw the money would be:

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2 years ago

Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items,

Ivanshal [37]

Answer:

77.64% probability that there will be 0 or 1 defects in a sample of 6.

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The true proportion of defects is 0.15

This means that $p = 0.15$

Sample of 6:

This means that $n = 6$

What is the probability that there will be 0 or 1 defects in a sample of 6?

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.15)^{0}.(0.85)^{6} = 0.3771$

$P(X = 1) = C_{6,1}.(0.15)^{1}.(0.85)^{5} = 0.3993$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3771 + 0.3993 = 0.7764$

77.64% probability that there will be 0 or 1 defects in a sample of 6.

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3 years ago

Meg is starting a day-care center for the people in her community. She decided to charge $25 per day per child, out of which $5

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If I figured correctly it is 5 kids. Sorry if wrong!

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A moving company wants to buy a new type of truck and needs to know the volume of the storage compartment before they can decide

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