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s344n2d4d5 [400]
3 years ago
6

Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week

.
Part A: Create an equation that shows the amount of wages earned, W, for working x hours in a week when there is no overtime. (3 points)

Part B: Create an equation that shows the amount of wages earned, S, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 40 hours. (3 points)

Part C: Drey earned $490 in 1 week. How many hours (regular plus overtime) did he work? (4 points)
Mathematics
1 answer:
german3 years ago
4 0
Part A) x hours a week.
10$ per hour.

W= x*10.

Part B) 40 hours a week for 10$ each.

40*10 = 400.

Plus Y hours over time at 15$ each.
S=400+15y
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Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies ac
Shtirlitz [24]

Answer:

a) \mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

b) For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

Step-by-step explanation:

Assuming this question : "Bigger animals tend to carry their young longer before birth. The  length of horse pregnancies from conception to birth varies according to a roughly normal distribution with  mean 336 days and standard deviation 6 days. Use the 68-95-99.7 rule to answer the following questions. "

(a) Almost all (99.7%) horse pregnancies fall in what range of lengths?

First we need to remember the concept of empirical rule.

From this case we assume that X\sim N(\mu = 336. \sigma =6) where X represent the random variable "length of horse pregnancies from conception to birth"

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

From the empirical rule we know that we have 99.7% of the data within 3 deviations from the mean so then we can find the limits for this case with this:

\mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

(b) What percent of horse pregnancies are longer than  342 days?

For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

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